Answer:4m/s
Explanation:The car is moving with constant acceleration therefore average speed is equal to distance over time to find the distance covered we multiple the speed by the time which gives 20 metres meaning after every 20 metres it uses a speed of 2m/s so for 40 metres it's going to be 40 x2 over 20 giving us 4m/s
Answer: First shot
Explanation:
A) Distance of puck from goal during the first shot = 5m away
Speed of puck during first shot = 10m/s
Time taken to score = ?
Since speed is the distance covered per unit time
i.e speed = Distance / time taken
Time taken = Distance / Speed
Time taken = 5m / 10m/s
= 0.5 seconds
B) Distance of puck from goal during the second shot = 10m away
Speed of puck during second shot = 40m/s
Time taken to score = ?
Recall that time taken = (Distance / Speed)
Time taken = 10m / 40m/s
= 0.25 seconds
It will take 0.5 seconds for the first shot to score whereas it will takes 0.25 seconds for the second shot to score.
Thus, the goalie have a better chance of blocking the first shot since it is slower than the second.
A. Acceleration is the answer to you question. When an object changes velocity it can accelerate.<span />
Answer:
6J
Explanation:
Given parameters:
Mass of fish = 1kg
Velocity = 12m/s
Unknown:
Change in kinetic energy = ?
Solution:
Kinetic energy is the energy due to the motion of a body. It is mathematically given as:
K.E = m v²
Now, insert the parameters and solve;
K.E = x 1 x 12 = 6J
The change in kinetic energy is 6J
Answer:
U = 9.1 m/s
Explanation:
from the question we are given the following
time (t) = 1.8 s
angle = 23 degrees
acceleration due to gravity (g) = 9.8 m/s^{2}
let us first calculate the initial velocity (u) which too the first ball to its maximum height from the equation below
v = u + 0.5at
- The final velocity (v) is zero since the ball comes to rest
- The time (t) it takes to get to the maximum height would be half the time it is in the air, t = 0.5 x 1.8 = 0.9
therefore
0 = u - (0.5 x 9.8 x 0.9)
u = 7.9 m/s
for the second ball to get to the maximum height of the first ball, the vertical component of its initial velocity (U) must be the same as the initial velocity of the first ball. therefore
U sin 60 = 7.9
U = 7.9 ÷ sin 60
U = 9.1 m/s