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noname [10]
2 years ago
12

Find the change in kinetic energy of a 1.0 kg fish leaping to the right at 12.0 m/s.

Physics
2 answers:
WARRIOR [948]2 years ago
8 0

Answer:

Hey yall, the answer is 72 J.

Explanation:

sp2606 [1]2 years ago
4 0

Answer:

6J

Explanation:

Given parameters:

Mass of fish  = 1kg

Velocity  = 12m/s

Unknown:

Change in kinetic energy = ?

Solution:

Kinetic energy is the energy due to the motion of a body. It is mathematically given as:

       K.E  = \frac{1}{2}  m v²  

Now, insert the parameters and solve;

  K.E  =  \frac{1}{2}  x 1 x 12  = 6J

The change in kinetic energy is 6J

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3 0
3 years ago
A 3.91 kg cart is moving at 5.7 m/s when it collides with a 4 kg cart which was at rest. They collide and stick together.
Nesterboy [21]

Answer:

<em>The velocity after the collision is 2.82 m/s</em>

Explanation:

<u>Law Of Conservation Of Linear Momentum </u>

It states the total momentum of a system of bodies is conserved unless an external force is applied to it. The formula for the momentum of a body with mass m and speed v is  

P=mv.  

If we have a system of two bodies, then the total momentum is the sum of the individual momentums:

P=m_1v_1+m_2v_2

If a collision occurs and the velocities change to v', the final momentum is:

P'=m_1v'_1+m_2v'_2

Since the total momentum is conserved, then:

P = P'

Or, equivalently:

m_1v_1+m_2v_2=m_1v'_1+m_2v'_2

If both masses stick together after the collision at a common speed v', then:

m_1v_1+m_2v_2=(m_1+m_2)v'

The common velocity after this situation is:

\displaystyle v'=\frac{m_1v_1+m_2v_2}{m_1+m_2}

There is an m1=3.91 kg car moving at v1=5.7 m/s that collides with an m2=4 kg cart that was at rest v2=0.

After the collision, both cars stick together. Let's compute the common speed after that:

\displaystyle v'=\frac{3.91*5.7+4*0}{3.91+4}

\displaystyle v'=\frac{22.287}{7.91}

\boxed{v' = 2.82\ m/s}

The velocity after the collision is 2.82 m/s

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2 years ago
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Answer:

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2. Har (every)

3. Kal (tomorrow)

4. Mat (don't)

5. Andar (inside)

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A stone is dropped from a cliff. after it has fallen 10m what is the stones velocity
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