V=4/3πr^3
36π=4/3πr^3
3/4(36π)=(4/3πr^3)3/4
27π=πr^3
π(27π)=r^3
27=r^3
square root
r=3
s.a=4πr^2
s.a=4π(3^2)
s.a=4π(9)
s.a=36π
Answer:
1040 tehyimngtumh
Step-by-step explanation:
Apex
Answer:
B. HL
Step-by-step explanation:
Answer:
should i simplify it? or factorise it?
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x^2+16+64
(x)^2+2×x×8+(8)^2
(x+8)^2
=(x+8)(x+8)
The last answer: 2 or 0
Explanation:
When you graph this function, it crosses the x-axis once. In other words, that means there is only 1 real zero and 2 imaginary complex zeros. In addition, imaginary solutions always come in pairs, so there can’t be a odd number of them such as 3.
