Answer:
okb-joye-ngv
C O m e t o l e a r n s e x
or m a k e s e x
Answer:
Since the line is not scaled, then how do we know for sure. But, we do know that point A is the opposite of point C. For example, if C = 150, then A = -150
Step-by-step explanation:
Since the line is not scaled, then how do we know for sure. But, we do know that point A is the opposite of point C. For example, if C = 150, then A = -150
Answer:
tanA=34⟹sinA=332+42−−−−−−√=35
Now, we have
sinAcosA=tanA
⟹3/5cosA=tanA
⟹cosA=13×54×3
⟹cosA=45
⟹cosAsinA=4×35×5=1225
Step-by-step explanation:
Hello,
++++++++++++++++
f(x)=a(x-6)²+2
f(0)=-70==>a(-6)²+2=-70===>36a=-72==>a=-2
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Answer:
Step-by-step explanation:
I'm going to assume you mean passes through the point (-2,5) since -2 and 5 could mean a lot of different things
To find the perpendicular line's gradient, you would know that m1*m2 = -1
In this case m1 = 7, so m2 must be -1/7
Now we substitute the gradient into the equation
y = -1/7x + b
To find b, we substitute (-2,5) into the equation above
5 = -1/7*-2+b
5 = 2/7 + b
b = 33/7
Therefore the equation of the line is
y = -1/7x+33/7
