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3 years ago

approximately how many grams of sodium chloride (NaCl) are required to prepare 500. mL of 3.00 M solution

1 answer:

4 0

3.00 M means 3.00 mol/L. So if you want 500 mL=0.5 L, it needs 3.00 mol/L * 0.5 L = 1.50 mol. For NaCl, the molar mass is 23+35.5=58.5 g/mol. So the amount of NaCl needed is 1.50*58.5=87.75 g. So the answer is 87.75 grams.

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A solution (HELP ASSAAAAP ROAD TO GRADUATION)

creativ13 [48]

Hey there! A simple explanation is below.

Answer:

D) is a single phase homogeneous mixture.

Explanation:

A solution is a form of homogenous combination made up of two or more components in chemistry. A solute is a material that is dissolved in another material, known as a solvent, in such a combination. The mixing of a solution takes place at a scale where the effects of chemical polarity are present, resulting in solvation-specific interactions. In most cases, the solution is in the condition of the solvent, because it is most common in the mixture.

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3 years ago

What volume of oxygen is needed to react with 20cm3 of ethane?

Anna71 [15]

Answer:

The reaction states that 2 moles of ethane react with 7 moles of oxygen. At standard temperature and pressure conditions (STP), each mole of gas occupies a volume of 22.4 liters. Therefore, 2 moles of ethane occupy liters, and 7 moles of oxygen occupy liters. In other words: 6 liters.

Explanation:

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3 years ago

How many grams of sulfur will react with 6.75 g of silver? How many grams of silver sulfide (Ag2S) will be formed in this reacti

Xelga [282]

Solve the following equation and check for extraneous solutions. Show all work. Thank you.

sqrt(sqrt(x - 3)) = sqrt(x - 15)

8 0

2 years ago

Substitute natural gas (SNG) is a gaseous mixture containing CH4(g) that can be used as a fuel. One reaction for the production

Lynna [10]

Answer:

ΔH° of the reaction is -747.54kJ

Explanation:

Based on gas law, it is possible to find the ΔH of a reaction using ΔH of half reactions.

Using the reactions:

(1) C(graphite) + 1/2O₂(g) → CO(g) ΔH° = -110.5 kJ

(2) CO(g) + 1/2O₂(g) → CO₂(g) ΔH° = -283.0 kJ

(3) H₂(g) + 1/2O₂(g) → H₂O(l) ΔH° = -285.8 kJ

(4) C(graphite) + 2H₂(g) → CH₄(g) ΔH° = -74.81 kJ

(5) CH₄(g) + 2O₂(g) → CO₂(g) + 2H₂O(l) ΔH° = -890.3 kJ

The sum of 4×(4) + (5) gives:

4C(graphite) + 8H₂(g) + 2O₂(g) → CO₂(g) + 2H₂O(l) + 3CH₄(g)

ΔH° = -74.81 kJ ×4 - 890.3 kJ = -1189.54kJ

Now, this reaction - 4×(1) gives:

4CO(g) + 8H₂(g) → CO₂(g) + 2H₂O(l) + 3CH₄(g)

ΔH° = -1189.54kJ - 4×-110.5 = -747.54kJ

Thus ΔH° of the reaction is -747.54kJ

3 0

3 years ago

Nitric acid, , is manufactured by the Ostwald process, in which nitrogen dioxide, , reacts with water. How many grams of nitroge

aleksandr82 [10.1K]

Answer:

7.04 g

Explanation:

Let's consider the reaction in the last step of the Ostwald process.

3 NO₂(g) + H₂O(l) → 2 HNO₃(aq) + NO(g)

The molar mass of HNO₃ is 63.01 g/mol. The moles corresponding to 6.40 g are:

6.40 g × (1 mol/63.01 g) = 0.102 mol

The molar ratio of NO₂ to HNO₃ is 3:2. The reacting moles of NO₂ are:

0.102 mol HNO₃ × (3 mol NO₂/2 mol HNO₃) = 0.153 mol NO₂

The molar mass of NO₂ is 46.01 g/mol. The mass corresponding to 0.153 moles is:

0.153 mol × (46.01 g/mol) = 7.04 g

5 0

3 years ago