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3 years ago

Solve for t 5t - 2 = 6t - 7

Mathematics

1 answer:

Dmitry_Shevchenko [17]3 years ago

3 0

Answer:

The answer to the question is 5 (positive 5)

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Factor completely x3 + 4x2 + 8x + 32. (x + 4)(x2 + 8) (x − 4)(x2 − 8) (x − 4)(x2 + 8) (x + 4)(x2 − 8)

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$\tt x^3+4x^2+8x+32\\\\=x^2(x+4)+8(x+4)\\\\=\boxed{\tt(x+4)(x^2+8)}$

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3 years ago

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Find the area of the parallelogram: b= 10 ft, h= 8 ft

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Find the least number which when divisible by 20, 24, 32 and 38 leaves a remainder 5 in cach case

Olegator [25]

Answer:

18245

Step-by-step explanation:

We have to use L.C.M,

L.C.M(20,24,32,38)

2|20,24,32,38

2| 10 ,12 ,16 ,19

2| 5 , 6 , 8 , 19

2| 5 , 3 , 4 , 19

2| 5 , 3 , 2 , 19

L.C.M = 2 x 2 x 2 x 2 x 2 x 2 x 5 x 3 x 19

= 18240

Now for each case remainder is 5,

So the number is 18240+5

=> 18245

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3 years ago

Please help me it is due tonight

Aneli [31]

Answer: with what

Step-by-step explanation:

8 0

3 years ago

9/20

Stella [2.4K]

Question:

Find the number of real number solutions for the equation. x^2 + 5x + 7 = 0

Answer:

The number of real solutions for the equation $x^{2}+5 x+7=0$ is zero

Solution:

For a Quadratic Equation of form : $a x^{2}+b x+c=0$ ---- eqn 1

The solution is $x=\frac{-b \pm \sqrt{b^{2}-4 a c}}{2 a}$

Now , the given Quadratic Equation is $x^{2}+5 x+7=0$ ---- eqn 2

On comparing Equation (1) and Equation(2), we get

a = 1 , b = 5 and c = 7

In $x=\frac{-b \pm \sqrt{b^{2}-4 a c}}{2 a}$ , $b^2 - 4ac$ is called the discriminant of the quadratic equation

Its value determines the nature of roots

Now, here are the rules with discriminants:

1) D > 0; there are 2 real solutions in the equation

2) D = 0; there is 1 real solution in the equation

3) D < 0; there are no real solutions in the equation

Now let solve for given equation

$D= b^2 - 4ac\\\\D = 5^2 - 4(1)(7)\\\\D = 25 - 28 \\\\D = -3$

Since -3 is less than 0, this means that there are 0 real solutions in this equation.

4 0

3 years ago