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Dvinal [7]
3 years ago
12

Which three test points could be used to draw the graph of the solutions to x² + 4x-3>0

Mathematics
1 answer:
hram777 [196]3 years ago
8 0

(2,2),(3,1),(5,2)

---

hope it helps

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Round your answer to the nearest tenth.<br> y = 2x + 7 y=2x-2
Jet001 [13]

Answer:

no solution

Step-by-step explanation:

when you put in what y equals you get 2x-2=2x+7

8 0
3 years ago
PLEASE HELP ME ON THIS ONE I REALLY DONT KNOW HOW TO DO THIS AND I JUST CAME TO AMERICA SO I DONT KNOW HOW TO DO THESE THINGS CO
eimsori [14]

a: Answer is cuboid

b: top & base will be 5*6 = 30 in ^2

both right & left side wil be 5*2 = 10 in^2

front & back will be 6*2 = 12 in^2

Hope that will help you :)

5 0
3 years ago
I need help ASAP.I need help graphing this problem
Viktor [21]

Answer:

The answer to your question is below

Step-by-step explanation:

Each square values two units

I hope it helps you.

8 0
4 years ago
Here is a triangular pyramid and its net.
bazaltina [42]

Answer:

a) Area of the base of the pyramid = 15.6\ mm^{2}

b) Area of one lateral face = 24\ mm^{2}

c) Lateral Surface Area = 72\ mm^{2}

d) Total Surface Area = 87.6\ mm^{2}

Step-by-step explanation:

We are given the following dimensions of the triangular pyramid:

Side of triangular base = 6mm

Height of triangular base = 5.2mm

Base of lateral face (triangular) = 6mm

Height of lateral face (triangular) = 8mm

a) To find Area of base of pyramid:

We know that it is a triangular pyramid and the base is a equilateral triangle. \text{Area of triangle = } \dfrac{1}{2} \times \text{Base} \times \text{Height} ..... (1)\\

{\Rightarrow \text{Area of pyramid's base = }\dfrac{1}{2} \times 6 \times 5.2\\\Rightarrow 15.6\ mm^{2}

b) To find area of one lateral surface:

Base = 6mm

Height = 8mm

Using equation (1) to find the area:

\Rightarrow \dfrac{1}{2} \times 8 \times 6\\\Rightarrow 24\ mm^{2}

c) To find the lateral surface area:

We know that there are 3 lateral surfaces with equal height and equal base.

Hence, their areas will also be same. So,

\text{Lateral Surface Area = }3 \times \text{ Area of one lateral surface}\\\Rightarrow 3 \times 24 = 72 mm^{2}

d) To find total surface area:

Total Surface area of the given triangular pyramid will be equal to <em>Lateral Surface Area + Area of base</em>

\Rightarrow 72 + 15.6 \\\Rightarrow 87.6\  mm^{2}

Hence,

a) Area of the base of the pyramid = 15.6\ mm^{2}

b) Area of one lateral face = 24\ mm^{2}

c) Lateral Surface Area = 72\ mm^{2}

d) Total Surface Area = 87.6\ mm^{2}

3 0
3 years ago
The express the area of the entire rectangle
Sonja [21]

Answer:

area= x^2+8x+7

Step-by-step explanation:

a=l*w

l=x+7

w=x+1

a=(x+7)(x+1)

a= x^2+8x+7

5 0
3 years ago
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