Answer:
V2=-20.0155m/s
Step-by-step explanation:
To answer this question we will use the principle of conservation of momentum which is
MtVt=M1V1+M2V2
1) let's find the initial velocity.
We will use,
v=a*t
v=10m/s2*2s = 20 m/s
d=vot+1/2*a*t2
d=0+1/2*10*4
d=20m
2) For the speed of the lighter piece we use,
v22=v12+2ad
0=v12+2*-9.81*(530-20)
v12=10006.2
v1=100.031m/s
3) Computing this in our conservation of momentum equation it will be-
MtVt=M1V1+M2V2
1500kg*20m/s=(1500*1/3)kg*100.031m/s + (1500*2/3)+V2
30000=50015.5+1000V2
Therefore V2=-20.0155m/s.
Just think of slope as the rate of change
Step-by-step explanation:
1. 156.15
2. 12335.85
3. 182.33
4. 8934.17
√65 units is the answer
the approx. distance is 8.0622577
Answer:
Step-by-step explanation:
Hello,
we can notice that
so 1 is the missing constant term to get a perfect square
hope this helps
