Which three test points could be used to draw the graph of the solutions to x² + 4x-3>0
1 answer:
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Answer:
The point P(1,-3) is not a solution to the system.
Step-by-step explanation:
Given
Let a point be P(1,-3)
Here x = 1 ; y = -3
Substituting the values of x,y in the function
For y<x-1
-3 < 1-1
-3<0 (True)
now for,
y>-x+2
-3 > -1 + 2
-3 > 1 (False)
Hence the point is not a solution to the system.
Place the decimal point right after the first nonzero digit, which is 3.
So you'll go from this
to this 
after this move.
Now ask yourself: "how many spots must I move the decimal point to get back to 0.003045?"
The answer is "3 spots to the left"
The exponent of the final answer is -3
The negative indicates "move left" and the 3 tells us how many places to move the decimal
Therefore,
Answer: Choice C)
This is assuming you meant to write the -3 as an exponent
So you'll go from this
Now ask yourself: "how many spots must I move the decimal point to get back to 0.003045?"
The answer is "3 spots to the left"
The exponent of the final answer is -3
The negative indicates "move left" and the 3 tells us how many places to move the decimal
Therefore,
Answer: Choice C)
This is assuming you meant to write the -3 as an exponent
Answer:
The probability that the mean test score is greater than 290
P(X⁻ > 290 ) = 0.0217
Step-by-step explanation:
<u><em>Step(i):</em></u>-
Mean of the Population (μ) = 281
Standard deviation of the Population = 34.4
Let 'X' be a random variable in Normal distribution
Given X = 290
<u><em>Step(ii):-</em></u>
<em> The probability that the mean test score is greater than 290</em>
P(X⁻ > 290 ) = P( Z > 2.027)
= 0.5 - A ( 2.027)
= 0.5 - 0.4783
= 0.0217
The probability that the mean test score is greater than 290
P(X⁻ > 290 ) = 0.0217