Calculate the equivalent resistance of three resistances R1 = 2 Ω , R2 = 5 Ω and R3 = 11 Ω , if they are arranged such that the
1 answer:
Answer:
The equivalent resistance is equal to 18 Ω.
Explanation:
The given resistors are 2 Ω, 5 Ω and 11 Ω.
They are arranged such that the current flowing through all three resistances is the same. It means the resistors are connected in a series combination.
The equivalent resistance in series combination is given by :
So, the equivalent resistance is equal to 18 Ω.
You might be interested in
Answer:
Explanation:
<u>Instant Acceleration</u>
The kinetic magnitudes are usually related as scalar or vector equations. By doing so, we are assuming the acceleration is constant over time. But when the acceleration is variable, the relations are in the form of calculus equations, specifically using derivatives and/or integrals.
Let f(t) be the distance traveled by an object as a function of the time t. The instant speed v(t) is defined as:
And the acceleration is
Or equivalently
The given height of a projectile is
Let's compute the speed
And the acceleration
It's a constant value regardless of the time t, thus
Answer:
1) It expresses the rate (top speed) at which it can move with time.
2) P = 20 W
3) h = 18 km
Explanation:
1) Power is the rate of transfer of energy.
⇒ Power =
i.e P =
Thus a car's engine power is 44000W implies that the engine of the car can propel the car at this rate. This expresses the rate (top speed) at which it can move with time.
2) m = 400g = 0.4 kg
t = 20 s
h = 100m
g = 10 m/
P =
=
=
P = 20 W
3) u = 600 m/s
g = 10 m/
From the third equation of free fall,
=
- 2gh
V is the final velocity, U is the initial velocity, h is the height.
0 = - 2 x 10 x h
0 = 360000 - 20h
20h = 360000
h =
= 18000
h = 18 km
The maximum height of the bullet would be 18 km.