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Lina20 [59]
4 years ago
12

Two circuits have identical voltage sources. The only other elements in the circuits are resistors. The resistor in circuit A ha

s a resistance that is four times as large as the resistance of the resistor in circuit B (RA = 4RB ). Which statement below best describes the current flowing through the two circuits? (Ohm's law: V = IR) A. The current flowing through circuit A is as large as the current flowing through circuit B. B. The current flowing through circuit A is 2 times as large as the current flowing through circuit B. C. The current flowing through circuit A is 4 times as large as the current flowing through circuit B. D. The current flowing through circuit A is as large as the current flowing through circuit B.
Physics
1 answer:
12345 [234]4 years ago
7 0
The correct answer is not included among the choices you posted.
That may have happened because you mistakenly copied the wrong
text for choice A or D .... As the question appears, those two choices
are the same thing.

The correct answer is:
The current in circuit-A is 1/4 of the current in circuit-B.
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The temperature of water in a beaker is 45°C. What does this measurement represent
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Based on my information, this would actually be representing "the average kinetic energy of water particles". So, as you take notice that where this temperature is being located, and also, how this would be 45°C, this would make more sense for this to be representing as <span>the average kinetic energy of water particles.</span>
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A sample contains 20 kg of radioactive material. The decay constant of the material is 0.179 per second. If the amount of time t
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Answer:

Explanation:

Given

N0 = 20kg (original substance)

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time t = 300s

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n(t) = N0e^-λt

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3 years ago
As a stunt for movie two cars are to collide with each other head on. The two cars are initially 125 apart. Car A is heading str
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Answer:

3.39724 seconds

23.0824792352 m, 101.917520765 m

13.58896 m/s

Explanation:

t = Time taken

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v = Final velocity

s = Displacement

a = Acceleration

The equation of motion will be

s=ut+\dfrac{1}{2}at^2\\\Rightarrow 125=30\times t+\dfrac{1}{2}\times 4\times t^2\\\Rightarrow 2t^2+30t-125=0\ m

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The time at which the cars collide is 3.39724 seconds

s=ut+\dfrac{1}{2}at^2\\\Rightarrow s=0\times t+\dfrac{1}{2}\times 4\times 3.39724^2\\\Rightarrow s=23.0824792352\ m

Car B traveled 23.0824792352 m and Car A traveled 125-23.0824792352 = 101.917520765 m

v=u+at\\\Rightarrow v=0+4\times 3.39724\\\Rightarrow v=13.58896\ m/s

The speed of car B is 13.58896 m/s

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