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Lina20 [59]
3 years ago
12

Two circuits have identical voltage sources. The only other elements in the circuits are resistors. The resistor in circuit A ha

s a resistance that is four times as large as the resistance of the resistor in circuit B (RA = 4RB ). Which statement below best describes the current flowing through the two circuits? (Ohm's law: V = IR) A. The current flowing through circuit A is as large as the current flowing through circuit B. B. The current flowing through circuit A is 2 times as large as the current flowing through circuit B. C. The current flowing through circuit A is 4 times as large as the current flowing through circuit B. D. The current flowing through circuit A is as large as the current flowing through circuit B.
Physics
1 answer:
12345 [234]3 years ago
7 0
The correct answer is not included among the choices you posted.
That may have happened because you mistakenly copied the wrong
text for choice A or D .... As the question appears, those two choices
are the same thing.

The correct answer is:
The current in circuit-A is 1/4 of the current in circuit-B.
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5 0
2 years ago
If the distance from a light source triples, how does light intensity change? The intensity will be 3x greater. The intensity wi
Tcecarenko [31]

Answer:

The intensity will be 1/9 as much.

Explanation:

The intensity of the light or any source is inversely related to the square of the distance.

I\alpha \frac{1}{r^{2} }

Now according to the question the distance is increased by three times than,

\frac{I_{2} }{I_{1} }=\frac{r_{1}^{2} }{r_{2}^{2} }

Therefore,

\frac{I_{2} }{I_{1} }=\frac{r_{1}^{2} }{(3r_{1})^{2} }\\\frac{I_{2} }{I_{1} }=\frac{1}{9} \\{I_{2}=\frac{1}{9}{I_{1} }

Therefore the intensity will become 1/9 times to the initial intensity.

3 0
3 years ago
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Answer:

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Explanation:

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3 years ago
Read 2 more answers
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