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lisov135 [29]
3 years ago
11

Which of the following is an example of potential energy?

Physics
1 answer:
siniylev [52]3 years ago
7 0
Water behind a tall dam, a bowling ball on a high shelf, and a 
roller coaster at the top of the first hill, are examples of gravitational
potential energy.

A stretched rubber band, and a compressed spring, are examples
of elastic potential energy.

A battery and a sugar cookie are examples of chemical potential energy.
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Which example identifies a change in motion that produces acceleration? choices are: 1. a speed skater moving at a constant spee
Oduvanchick [21]
Acceleration is a vector quantity that takes into account the changes in either the direction or the velocity or both. From the choices given, I go with choice number 2 where the body moves in a circular motion; thus, causing changes in its direction from time to time.
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3 years ago
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A lemming running 3.22 m/s runs off a horizontal cliff. It lands in the water 7.54 m from the base of the cliff. How much time w
LekaFEV [45]

Answer: 2.34s

Explanation:

Given the following :

Horizontal Velocity(V) = 3.22m/s

Horizontal Distance = 7.54m

Therefore, the time spent in the air can be calculated thus:

Using the relation:

Speed = distance / time

3.22m/s = 7.54m / time

Time = 7.54m / 3.22m/s

Time = 2.34s

7 0
3 years ago
Who knows how to do this?
stepladder [879]

I do, and my brother and son-in-law can also solve it.

Note: V1, V2, V3, I1, I2, and I3 are not labeled in the picture, so those can't be solved for.

7 0
3 years ago
A graduated cylinder is filled with water to the 24-mL mark. When a rock is placed in the cylinder, the level rises to the 53-mL
harkovskaia [24]
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6 0
3 years ago
The bob (weight) at the end of a pendulum has a mass of 0.3 kilograms. The bob is pulled to position B and allowed to swing. It
Ivahew [28]

Answer:

0.147 J

Explanation:

The total energy that has been transformed into thermal energy is equal to the loss of gravitational potential energy between the initial situation (bob at h=0.5 m above the ground) and the final situation (bob back but at h=0.45 m above the ground).

Therefore, we have

E_{thermal}=\Delta U=mgh_1 - mgh_2 = mg(h_1 -h_2)

where

m = 0.3 kg is the mass of the bob

g = 9.8 m/s^2

h1 = 0.5 m is the initial height

h2 = 0.45 m is the final height

Substituting, we find the thermal energy

E_{thermal}=(0.3 kg)(9.8 m/s^2)(0.5 m-0.45 m)=0.147 J

Therefore, the energy transformed into thermal energy is 0.147 J.

3 0
3 years ago
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