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lisov135 [29]
3 years ago
11

Which of the following is an example of potential energy?

Physics
1 answer:
siniylev [52]3 years ago
7 0
Water behind a tall dam, a bowling ball on a high shelf, and a 
roller coaster at the top of the first hill, are examples of gravitational
potential energy.

A stretched rubber band, and a compressed spring, are examples
of elastic potential energy.

A battery and a sugar cookie are examples of chemical potential energy.
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A snail is at the bottom of a well, 115 feet deep. On day 1, it starts climbing up the side. That night it rests and slips down
julia-pushkina [17]

Answer:

Number of days needed = 57

Explanation:

Depth of well = 115 feet

Distance traveled in day = 3 feet up

Distance traveled in night = 1 feet down.

Total displacement in 1 day = 3 - 1 = 2 feet up

When the snail reaches 112 feet up, the next 3 feet up motion on day will make it reach the top.

\texttt{Days to travel 112 feet up = }\frac{112}{2}=56

After 56 days the displacement of snail is 112 feet.

On the next day it moves up by 3 feet and reaches out of well.

Number of days needed = 57

4 0
3 years ago
The voltage in a circuit is given by the equation V = IR . In this equation , Vis the voltage, the current, and Ris the resistan
Mumz [18]

Answer:

The choice D.

R =  \frac{v}{I}

I hope I helped you^_^

8 0
3 years ago
A charge in motion is called a (n) ______.
Lubov Fominskaja [6]
<span>It's called an electric current</span>
7 0
3 years ago
Read 2 more answers
What occurs when waves overlap
IrinaK [193]
If you are talking about ocean waves crashing into each other, they would probably mostly cancel out with just a bit of motion left over. If you are talking about things like frequency and amplitude, overlapping waves would combine and amplify or suppress each other, depending on their direction, position, frequency and amplitude. If the two waves complement each other, they amplify; if they conflict with each other, they are suppressed.
5 0
3 years ago
A bystander observes the musicians heading toward each other. When musician #1 is 100 m away, the intensity is 1.24 x 10-8 W/m^2
777dan777 [17]

Explanation:

Given that,

Distance 1, r = 100 m

Intensity, I_1=1.24\times 10^{-8}\ W/m^2

If distance 2, r' = 25 m

We need to find the intensity and the intensity level at 25 meters. Intensity and a distance r is given by :

I=\dfrac{P}{4\pi r^2}.........(1)

Let I' is the intensity at r'. So,

I'=\dfrac{P}{4\pi r'^2}............(2)

From equation (1) and (2) :

I'=\dfrac{Ir}{r'^2}

I'=\dfrac{1.24\times 10^{-8}\times 100}{25^2}

I'=1.98\times 10^{-9}\ W/m^2

Intensity level is given by :

dB=10\ log(\dfrac{I'}{I_o}), I_o=10^{-12}\ W/m^2

dB=10\ log(\dfrac{1.98\times 10^{-9}}{10^{-12}})

dB = 32.96 dB

Hence, this is the required solution.

7 0
3 years ago
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