Answer:
D. 108 grams of KNO3(Potassium nitrate)
The volume of the gas at a temperature of 405.0 K would be 607.5 mL. Making option D the right answer to the question.
What is the volume of the gas?
To find the volume of the gas, the equation to be used would have to be combine gas law.
Combine gas law as the name suggest uses the combination of Charles law which measures Volume against temperature, and Gay-Lussac's law which measures Pressure/Temperature, and Boyle's law which measures pressure X volume where k is constant.
Using the combine law to find the volume, we have:
P₁V₁/T₁=P₂V₂/T₂
Where P₁ = initial pressure
V₁ = initial volume
T₁ = initial temperature
P₂ = final pressure
V₂ = final volume
T₂ = final temperature
P₁ = 2.25atm
V₁ = 450.0 mL
T₁ = 300 K
T₂ = 405.0 K
V₂ = ?
D) 607.5 mL
= [2.25(450)]÷300=[2.25(V₂]÷405
Making V₂ the subject
3.375=2.25 V₂ ÷ 405
V₂ = 3.375 x 405 ÷ 2.25
V₂ = 607.5 mL
In summary, a gas with an initial pressure of 2.25atm, an initial pressure of 450.0 mL and an initial temperature of 300 K would have a final volume of 607.5 mL if the temperature is increased to 405.0 K.
Learn more about Combine gas law here: brainly.com/question/13538773
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On the off chance that one of the reactants is in overabundance yet you don't know which one it is, you have to compute the hypothetical item mass for the both reactants, with a similar item, and whichever has the lower yield is the one you use to precisely depict masses/sums for the condition, since you can't have more than the non-abundance reactant can create.
