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2 years ago

If this experiment is repeated at a place3 meters above the sea level the acceleration due to gravity is expected to

1 answer:

8 0

The question doesn't describe any experiment. If the same experiment is repeated, no matter how many times, the acceleration due to gravity will remain the same as it was during the non-existent original experiment, and will have no effect on anything.

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What would the velocity of an object be if it was on a 1.75m

JulijaS [17]

Answer:

T = 4 sec / 2 = 2 sec period of revolution

S = 2 pi R = 2 * pi * 1.75 m = 11 m

V = S / T = 11 m / 2 sec = 5.5 m/s speed of object

4 0

2 years ago

According to Newton's second law of motion, force can be calculated by multiplying an object's mass by its acceleration. If weig

madreJ [45]

You would do m*a so 65kg * 9.8 m/s^2 which equates to 637 Newton’s

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3 years ago

Suppose water waves are moving from the deep end to the shallow end of the pool. That is, the waves are moving into a medium (sh

MissTica

Answer:

The waves will turn slightly to the <em><u>left .</u></em>

Explanation :

The waves will turn slightly to the left, because the left side of each wave front hits the boundary first and slows down, moving more slowly than the right side until the right side of the wave front reaches the boundary. THis causes the wave to veer slightly to the left.

Basically the speed of water depends upon depth of the river or the ocean.

the formula is as follows :

v = √gxd

v = √d (g is the gravitational acceleration)

As the water waves are more at the deeper end then the shallow end, so during its course to the shallower end, they are slightly deviated toward the normal., hence it will move slightly to the left.

8 0

3 years ago

Read 2 more answers

Water drips from a faucet at the rate of 150 drops in 120 seconds. What is the period?

user100 [1]

Answer:

.80

Explanation:

7 0

3 years ago

Scientific work is currently underway to determine whether weak oscillating magnetic fields can affect human health. For example

ValentinkaMS [17]

Answer:

$2.02672\times 10^{-11}\ V$

Explanation:

f = Frequency = 75 Hz

B = Magnetic field = $1\times 10^{-3}\ T$

d = Diameter of cell = $7.4\ \mu m$

t = Time taken

$\omega$ = Angular frequency

The expression of emf is

$E=NAB\omega sin\omega t$

Emf is maximum when $sin\omega t=1$ and N = number of turns = 1

$E_m=AB\omega\\\Rightarrow E_m=\pi \left(\frac{d}{2}\right)^2 \times B \times 2\pi\times f\\\Rightarrow E_m=\pi \left(\frac{7.4\times 10^{-6}}{2}\right)^2\times 1\times 10^{-3}\times 2\pi\times 75\\\Rightarrow E_m=2.02672\times 10^{-11}\ V$

The maximum emf that can be generated around the perimeter of a cell in this field is $2.02672\times 10^{-11}\ V$

4 0

2 years ago