Question

A 12,000-N car is raised using a hydraulic lift, which consists of a U-tube with arms of unequal areas, filled with oil with a density of 800 kg/m3 and capped at both ends with tight-fitting pistons. The wider arm of the U-tube has a radius of 18.0 cm and the narrower arm has a radius of 5.00 cm. The car rests on the piston on the wider arm of the U-tube. The pistons are initially at the same level. What is the force that must be applied to the smaller piston in order to lift the car after it has been raised 1.20 m

Answer 1

Answer:

The answer is below

Explanation:

Pascal's law states that pressure is exerted in all parts of a static fluid equally.

The area of the narrower arm with a radius of 0.05 m (5 cm) is given as:

Area of narrow arm = π(0.05)²

The area of the wider arm with a radius of 0.18 m (18 cm) is given as:

Area of narrow arm = π(0.18)²

The ratio if the wider arm area to the narrow arm area = π(0.18)² / π(0.05)² = 12.96

To move the 12000 N car, the amount of force needed = 12000/12.96 = 926 N