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Korolek [52]
3 years ago
14

What are the x-intercepts of y = 4x^2 + 4x + 1?

Mathematics
2 answers:
Slav-nsk [51]3 years ago
8 0

Answer:

hope this helps:) have a good day

Evgen [1.6K]3 years ago
8 0

Answer:

-1/2 is the x vertex.

Step-by-step explanation:

(y = ax^2 + bx + c),

-(b)/2(a)

-(4)/2(4)

-4/8 = -1/2

-1/2 is x

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An adult ticket to the show costs $2 more than a student ticket. The total cost of 3 student tickets and 2 adult tickets is $39.
madreJ [45]

Answer:

An adults ticket costs $9

Step-by-step explanation:

Kids:

$7

Adults:

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So if you add 7+7+7= 21 (kids)

then do 9+9=18(adults)

Then add them together you get  39$

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Given cos C = cos N in triangle ABC and triangle LMN, select all of the true statements
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What are the statements to the equation
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3 0
3 years ago
According to a report from a business intelligence company, smartphone owners are using an average of 22 apps per month. Assume
Ira Lisetskai [31]

Answer:

0.4332 = 43.32% probability that the sample mean is between 21 and 22.

Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the central limit theorem.

Normal Probability Distribution:

Problems of normal distributions can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the z-score of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

Central Limit Theorem

The Central Limit Theorem establishes that, for a normally distributed random variable X, with mean \mu and standard deviation \sigma, the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean \mu and standard deviation s = \frac{\sigma}{\sqrt{n}}.

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

According to a report from a business intelligence company, smartphone owners are using an average of 22 apps per month.

This means that \mu = 22

Standard deviation is 4:

This means that \sigma = 4

Sample of 36:

This means that n = 36, s = \frac{4}{sqrt{36}}

What is the probability that the sample mean is between 21 and 22?

This is the p-value of Z when X = 22 subtracted by the p-value of Z when X = 21.

X = 22

Z = \frac{X - \mu}{\sigma}

By the Central Limit Theorem

Z = \frac{X - \mu}{s}

Z = \frac{22 - 22}{\frac{4}{sqrt{36}}}

Z = 0

Z = 0 has a p-value of 0.5.

X = 21

Z = \frac{X - \mu}{s}

Z = \frac{21 - 22}{\frac{4}{sqrt{36}}}

Z = -1.5

Z = -1.5 has a p-value of 0.0668.

0.5 - 0.0668 = 0.4332

0.4332 = 43.32% probability that the sample mean is between 21 and 22.

4 0
2 years ago
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