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3 years ago

What is a vector quantity?

Physics

1 answer:

Nat2105 [25]3 years ago

7 0

Answer:

A quantity that has magnitude and direction. It's usually represented by an arrow whose direction is the same direction is the same as that of the quantity and whose length is proportional to the quantity's magnitude

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A positive point charge is placed at 5 cm from a negatively charged plate.

Anastaziya [24]

Answer: I'm not sure about this one, but you can go to this link to understand it better https://youtu.be/wEQxtUwiV1E.Its a Khan Academy Video Hope This Helps

Explanation:

7 0

3 years ago

An object accelerates at 10 m/s2. If its starting velocity is 20 m/s and it travels for 30 seconds, what is its final velocity?

polet [3.4K]

Answer:

320m/s

Explanation:

Step 1: State your values

s= NOT NEEDED

u=20m/s

v=?

a=10m/s²

t=30 seconds

Step 2: Find a suitable suvat equation:

v=u+at

Step 3:

subsitute values into equation:

?=20+(10x30)

20+300

320m/s

8 0

3 years ago

Two manned satellites approach one another at a relative speed of 0.230m/s, intending to dock. The first has a mass of 4.50×103k

aliya0001 [1]

Answer:

$v_{f1}=-0.345m/s$ , $v_{f2}=0.23m/s$

Explanation:

The collision is elastically that's means that both mass restore their same value after the collision and don't have the same speed however the collision both satellites approach at the same velocity but in different direction to try to dock so:

$p_i=p_f$

$m_1*v_1+m_2*v_2=m_1*v_{f1}+m_{2}*v_{f2}$

$k_i=k_f$

$1/2*m_1*v_1^2+1/2*m_2*v_2^2=1/2*m_1*v_{f1}^2+1/2*m_1*v_{f2}^2$

Two equations and two variables to find solve to both finals velocities:

$v_{f1}=\frac{m_1-m_2}{m_1+m_2}*v_1+\frac{2*m_2}{m_1+m_2}*v_2$

$v_{f1}=-0.345m/s$

$v_{f2}=\frac{2*m_1}{m_1+m_2}*v_1+\frac{m_2-m_1}{m_1+m_2}*v_2$

$v_{f2}=0.23m/s$

6 0

3 years ago

A projectile is fired vertically with an initial velocity of 192 m/s. Calculate the maximum altitude h reached by the projectile

artcher [175]

Answer:

a) Maximum height reached = 1878.90 m

b) Time of flight = 39.14 seconds.

Explanation:

Projectile motion has two types of motion Horizontal and Vertical motion.

Vertical motion:

We have equation of motion, v = u + at, where v is the final velocity, u is the initial velocity, a is the acceleration and t is the time taken.

Considering upward vertical motion of projectile.

In this case, Initial velocity = vertical component of velocity = u sin θ, acceleration = acceleration due to gravity = -g $m/s^2$ and final velocity = 0 m/s.

0 = u sin θ - gt

t = u sin θ/g

Total time for vertical motion is two times time taken for upward vertical motion of projectile.

So total travel time of projectile , $t=\frac{2usin\theta }{g}$

Vertical motion (Maximum height reached, H) :

We have equation of motion, $v^2=u^2+2as$ , where u is the initial velocity, v is the final velocity, s is the displacement and a is the acceleration.