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Kitty [74]
3 years ago
15

The prominent semicircular space above a doorway in a Romanesque church portal is referred to as a ___________ and was often cov

ered in elaborate carvings
Physics
1 answer:
Ket [755]3 years ago
5 0

Answer: Tympanum

Explanation: A Tympanum could be described as the semicircular space above the doorway or window or entrance of a building. The space is usually designed using elaborate sculptural designs, Rocky costumes and ornaments. The tympanum could also be triangular-shaped and attributed to classical Greece and Roman architecture. It is usually located between the portals archivolt and the lintel. The tympanum is commonly observed in the churches and temples of ancient Rome and Greece.

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Someone answer? Please
dexar [7]
I don’t know ask your parents
6 0
2 years ago
Copper wire is 1. 9 mm in diameter and carries a current of 20 a. What is the electric field stregnth inside this wire?
Tju [1.3M]

The electric field strength will be 0.6252 V/m. It is the strength at which the field is created by charges.

<h3>What is electric file strength?</h3>

The electric field strength is defined as the ratio of electric force and charge.

The electric field strength is found as;

\rm E = \frac{I \rho }{A} \\\\ \rm E = \frac{20  \times 1.68 \times 10^{-8} }{ (0.6385 \times 10^{-6}} \\\\ E= 0.5262 \  V/m

Hence, the electric field strength will be 0.6252 V/m.

To learn more about the electric field strength, refer to the link;

brainly.com/question/4264413

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3 0
2 years ago
Three cars collide, a 1500 kg sports car, a 1750 kg family car, and a 1200 kg compact car. Which experiences the greatest change
sweet [91]

Answer:

d

Explanation:

This is because momentum is defined as p = mv

delta p = Force *time

neither velocity nor time is given so a conclusion cannot be made on which has the greatest momentum change.

5 0
3 years ago
In a solution of soda, the gaseous carbon dioxide is the solvent, and the liquid cola is the solute.
satela [25.4K]
I think its true but im not sure
4 0
3 years ago
An object has a mass of 48g and a volume of 6cm cubed (like a little 3 above the m) Calculate the density of this object
jonny [76]

       Density  =  (mass) / (volume)

                    =  (48 g)  /  (6 cm³)
 
                    =  (48 / 6)  (g / cm³)

                    =          8 g/cm³ 
                    
5 0
4 years ago
Read 2 more answers
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