Iron oxide reacts with aluminum to give aluminum oxide and iron. What kind of chemical reaction is this?

WA

brilliants [131]

Answer:

the answers the correct one is d

Explanation:

The speed of sound is constant so we can use the relations of uniform motion

v = x / t

x = v t

now let's calculate the distance for each person

t = 5s

x₁ = 300 5

x₁ = 1500 m

t = 6s

x₂ = 300 6

x₂ = 1800 m

therefore we have two possibilities

a) the two people are on the same side, therefore the distance between them is

Δx = x₂- x₁

Δx = 1800 - 1500

Δx = 300 m

let's reduce to km

Δx = 0.300 km

b) people are on opposite sides of the sound

Δx = x₂ + x₁

Δx = 1800 + 1500

Δx = 3300 m

Δx = 3.3 km

when checking the answers the correct one is d

3 0

2 years ago

When you put a pot of water on the stove, the stove transfers thermal energy to the water. As the water gains large

STALIN [3.7K]

Answer:

It releases some of the energy into the atmosphere as hot steam.

Explanation:

8 0

2 years ago

what is the mass of a pure platinum disk with a volume of 113 cm3? the density of platinum is 21.4 g/cm3

Oduvanchick [21]

V=m×d
m=v/d
m=113/21.4
m=5.28g

6 0

3 years ago

Read 2 more answers

An inductor has inductance of 0.260 H and carries a current that is decreasing at a uniform rate of 18.0 mA/s.

nignag [31]

Answer:

The self-induced emf in this inductor is 4.68 mV.

Explanation:

The emf in the inductor is given by:

$\epsilon = -L\frac{dI}{dt}$

Where:

dI/dt: is the decreasing current's rate change = -18.0 mA/s (the minus sign is because the current is decreasing)

L: is the inductance = 0.260 H

So, the emf is:

$\epsilon = -L\frac{dI}{dt} = -0.260 H*(-18.0 \cdot 10^{-3} A/s) = 4.68 \cdot 10^{-3} V$

Therefore, the self-induced emf in this inductor is 4.68 mV.

I hope it helps you!

6 0

3 years ago

Two sinusoidal waves are moving through a medium in the positive x-direction, both having amplitudes of 7.00 cm, a wave number o

lys-0071 [83]

Answer:

0.99 m

Explanation:

Parameters given:

Amplitude, A = 7.00cm

Wave number, k = 3.00m^-1

Angular Frequency, ω = 2.50Hz

Period = 6.00 s

Phase, ϕ = π/12 rad

Note: All parameters are the same for both waves except the phase.

Wave 1 has a wave function:

y1(x, t) = Asin(kx - ωt)

y1(x, t) = 7sin(3x - 2.5t)

Wave 2 has a wave function:

y2(x, t) = Asin(kx - ωt + ϕ)

y2(x, t) = 7sin(3x - 2.5t + π/12)

π is in radians.

When Superposition occurs, the new wave is represented by:

y(x, t) = 7sin(3x - 2.5t) + 7sin(3x - 2.5t + π/12)

y(x, t) = 7[sin(3x - 2.5t) + sin(3x - 2.5t + π/12)]

Using trigonometric function:

sin(a) + sin(b) = 2cos[(a - b)/2]sin[(a + b)/2]

Where a = 3x - 2.5t, b = 3x - 2.5t + π/12

We have that:

y(x, t) = (2*7)[cos(π/24)sin(3x - 2.5t + π/24)]

Therefore, when x = 0.53cm and t = 2s,

y(x, t) = (2*7)[cos(π/24)sin{(3*0.53) - (2.5*2)+ π/24}]

y(x, t) = 14 * 0.9914 * 0.0713

y(x, t) = 0.99 m

The height of the resultant wave is 0.99cm

5 0

2 years ago