During cellular respiration, organisms use oxygen to turn glucose into carbon dioxide, water, and energy in the form of ATP. The process has three stages: glycolysis , the Krebs cycle, and the electron transport chain. Glycolysis in the cytoplasm ), breaks down 1 glucose into 2 pyruvate and 2 ATP. The Krebs cycle (in the mitochondrion's matrix), provides the hydrogen and electrons needed for the electron transport chain. Another 2 are formed here. The electron transport chain (on the inner mitochondrial membrane) forms 32 ATP through oxidative phosphorylation .
Answer:
I am going to guess it shows that the balloon is going downwards because the speed of rise is in the negatives for the last 2.
Answer:
(c) 16 m/s²
Explanation:
The position is
.
The velocity is the first time-derivative of <em>r(t).</em>
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The acceleration is the first time-derivative of the velocity.
![a(t) = \dfrac{d}{dt} v(t) = -16\hat{j}](https://tex.z-dn.net/?f=a%28t%29%20%3D%20%5Cdfrac%7Bd%7D%7Bdt%7D%20v%28t%29%20%3D%20-16%5Chat%7Bj%7D)
Since <em>a(t)</em> does not have the variable <em>t</em>, it is constant. Hence, at any time,
![a = -16\hat{j}](https://tex.z-dn.net/?f=a%20%3D%20-16%5Chat%7Bj%7D)
Its magnitude is 16 m/s².
B. The sound of the engine will get louder and the pitch higher.
Answer:
16.63min
Explanation:
The question is about the period of the comet in its orbit.
To find the period you can use one of the Kepler's law:
![T^2=\frac{4\pi}{GM}r^3](https://tex.z-dn.net/?f=T%5E2%3D%5Cfrac%7B4%5Cpi%7D%7BGM%7Dr%5E3)
T: period
G: Cavendish constant = 6.67*10^-11 Nm^2 kg^2
r: average distance = 1UA = 1.5*10^11m
M: mass of the sun = 1.99*10^30 kg
By replacing you obtain:
![T=\sqrt{\frac{4\pi}{GM}r^3}=\sqrt{\frac{4\pi^2}{(6.67*10^{-11}Nm^2/kg^2)(1.99*10^{30}kg)}(1.496*10^8m)^3}\\\\T=997.9s\approx16.63min](https://tex.z-dn.net/?f=T%3D%5Csqrt%7B%5Cfrac%7B4%5Cpi%7D%7BGM%7Dr%5E3%7D%3D%5Csqrt%7B%5Cfrac%7B4%5Cpi%5E2%7D%7B%286.67%2A10%5E%7B-11%7DNm%5E2%2Fkg%5E2%29%281.99%2A10%5E%7B30%7Dkg%29%7D%281.496%2A10%5E8m%29%5E3%7D%5C%5C%5C%5CT%3D997.9s%5Capprox16.63min)
the comet takes around 16.63min