the assumption being "simple interest" rate of 3.8%, as opposed to "compound interest".
![\bf ~~~~~~ \textit{Simple Interest Earned Amount} \\\\ A=P(1+rt)\qquad \begin{cases} A=\textit{accumulated amount}\\ P=\textit{original amount deposited}\dotfill & \$5000\\ r=rate\to 3.8\%\to \frac{3.8}{100}\dotfill &0.038\\ t=years\dotfill &3 \end{cases} \\\\\\ A=5000[1+(0.038)(3)]\implies A=5000(1.114)\implies A=5570](https://tex.z-dn.net/?f=%5Cbf%20~~~~~~%20%5Ctextit%7BSimple%20Interest%20Earned%20Amount%7D%20%5C%5C%5C%5C%20A%3DP%281%2Brt%29%5Cqquad%20%5Cbegin%7Bcases%7D%20A%3D%5Ctextit%7Baccumulated%20amount%7D%5C%5C%20P%3D%5Ctextit%7Boriginal%20amount%20deposited%7D%5Cdotfill%20%26%20%5C%245000%5C%5C%20r%3Drate%5Cto%203.8%5C%25%5Cto%20%5Cfrac%7B3.8%7D%7B100%7D%5Cdotfill%20%260.038%5C%5C%20t%3Dyears%5Cdotfill%20%263%20%5Cend%7Bcases%7D%20%5C%5C%5C%5C%5C%5C%20A%3D5000%5B1%2B%280.038%29%283%29%5D%5Cimplies%20A%3D5000%281.114%29%5Cimplies%20A%3D5570)
To find a y-intercept, you set x=0 and solve for y.
y = 16(0) + 41
y = 41
PS
If the equation is in slope-intercept form like this, the y-intercept is always the number at the end, the "b" from y=mx+b.
Answer:
hope it helps :D
Let us assume the time after which both singers will charge the smae amount of money = x
Then
50 + 20x = 100 + 10x
20x -10x = 100 - 50
10x = 50
x = 50/10
= 5
So after 5 hours both Singer A and Singer B will charge the same amount of money. I hope the procedure is clear to you and you can attempt such problems in future without needing any kind of help.
Step-by-step explanation:
Infinitely amounts of solutions because -3y and 3y cancel each other out which means no matter what y is the outcome will always be 4.
