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3 years ago

Nickel and gold combine to make white gold. White gold is considered a(n) of nickel and gold.

2 answers:

8 0

White gold is considered an alloy of nickel and gold.
Alloy is the term which refers to the combination of metals, in which a new type of a metal is created. When you mix gold and some other white metal (such as nickel, palladium, or manganese), you get an alloy known as white gold.

faust18 [17]3 years ago

5 0

I think metal combinations are called alloy

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Physicist Richard Feyneman used to say, "Science is a way of trying not to

Leokris [45]

Answer:

nope

Explanation:

nopeee

6 0

3 years ago

The gas that a diver breathes must be maintained at a partial pressure of 0.20 atm of oxygen. More oxygen could poison the diver

Nimfa-mama [501]

<u>Answer:</u> The partial pressure of helium gas is 0.80 atm

<u>Explanation:</u>

Dalton's law of partial pressure states that the total pressure of the system is equal to the sum of partial pressure of each component present in it.

To calculate the partial pressure of helium gas, we use the law given by Dalton, which is:

$P_T=p_{He}+p_{O_2}$

We are given:

Total pressure of the cylinder, $P_T$ = 1.00 atm

Vapor pressure of oxygen gas, $p_{O_2}$ = 0.20 atm

Putting values in above equation, we get:

$1.00=p_{He}+0.20\\\\p_{He}=1.00-0.20=0.80atm$

Hence, the partial pressure of helium gas is 0.80 atm

5 0

3 years ago

i have an unknown volume of gas at a pressure of 0.50 atm a temperature of 325 k. If i raise the pressure to 1.2 atm, decrease t

Ronch [10]

Assuming that the number of mols are constant for both conditions:
$\frac{P_1V_1}{T_1} = \frac{P_2V_2}{T_2}$
Now you plug in the given values. V_1 is the unknown.
$\frac{0.50 atm*V_1}{325K} = \frac{1.2 atm* 48 L}{230K}
$
Separate V_1
$V_1= \frac{1.2 atm* 48 L * 325K }{230K*0.50 atm }$
V= 162.782608696 L

There are 2 sig figs

V= 160 L

3 0

3 years ago

What role does the reactivity of the reactants play in determining the rate of a chemical reaction?

Sonja [21]

What are the answer choices??

7 0

3 years ago

How many moles of Ca(OH)2 are needed to make 2.5 moles of CaCl2?

barxatty [35]

Explanation:

CaCl2 ⇄ Ca-²+2Cl-¹

1mole⇄1mole+2moles

So from above ..

1mole CaCl2 produce 1mole Ca-² & 2 moles of Cl-².

For 2.5 moles we multiply the above chemical eq. With 2.5

2.5CaCl2⇄2.5Ca-²+5Cl-¹

So from 2.5 moles of CaCl2 we get 2.5 mole calcium ion and 5 moles chloride ion…

5 0

2 years ago