Molarity of solution is expressed as,
Molarity =

Molecular weight of KCl = 74.55 g/mol
For preparing 1 mol of KCl solution (1 liter), 74.44 g KCl must be dissolved in 1 liter of water.
Following glasswares are required for preparing the solution.
1) Watch Glass (for weight the KCl)
2) Beaker (for preparing the solution)
3) Stirrer (For dissolving KCl in water)
4) Standard measuring flask (To ensure final volume of solution is 1 liter)
Answer:
27 g
Explanation:
M(C6H12O6) = 6*12 + 12*1 + 6*16 = 180 g/mol
100 mL = 0.1 L solution
1.5 M = 1.5 mol/L
1.5 mol/L * 0.1 L = 0.15 mol C6H12O6
0.15 mol * 180 g/1 mol = 27 g C6H12O6
Answer:
Es la tercera por qué cuando el material varía va cambiando de estado
Explanation:
Answer:
A. 1:3
Explanation:
If we look at the ions shown in the image attached to the question, we will notice that we have aluminum (Al^3+), a trivalent ion combining with the iodide ion (I^-).
Aluminum can easily give out its three outermost electrons to three atoms of iodine. If aluminum gives out its three electrons, it achieves the stable octet structure. Iodine atoms have seven electrons in their outermost shell. They only need one more electrons to complete their octet. This one electron can be gotten by the combination of three iodine atoms with one atom of aluminum. One electron each is transferred from the aluminum atom to each iodine atom to form AlI3 with a ratio of 1:3.