Ask question

Ask question

All categories

3 years ago

8

On the basis of the solubility curves shown above, the greatest percentage of which compound can be recovered by cooling a satur

ated solution of that compound from 90°C to 30°C? A) KCl B) NaNO3 C) NaCl D) KNO3

2 answers:

lys-0071 [83]3 years ago

6 0

The answer is D) KNO3

Nookie1986 [14]3 years ago

6 0

The answer is D) <span> <span> KNO3 </span> </span>

You might be interested in

Write complete ionic equation to show the reaction of aqueous hg2(no3)2 with aqueous sodium chloride to form solid hg2cl2 and aq

Andrews [41]

<span>Answer: Hg2(NO3)2 + 2 NaCl --------> Hg2Cl2 + 2 NaNO3 Hg2+2 + 2NO3-1 + 2Na+ Cl- ----> Hg2Cl</span>

5 0

3 years ago

Read 2 more answers

What happens to the ph of the reaction mixture as the oxidation reaction proceeds in an oxidation of an aromatic side chain?

andrew11 [14]

Answer:

The pH decreases.

Explanation:

Hello,

In organic chemistry, oxidation accounts for either the increasing of C-O bonds or the increasing in the oxygen atoms into the molecule. Thus, if we consider the oxidation from benzyl alcohol to benzoic acid, there will be a carboxyl functional group instead of a hydroxile one. Now, the presence of the polar -O-H bonds that are ionizable, there will be a $H^{+1}$ releasing causing the pH to decrease (increase acidity).

Regards.

4 0

2 years ago

Zoom anyone wants to join

FinnZ [79.3K]

Send the link code I’ll join

6 0

2 years ago

Read 2 more answers

All elements can be classified as metals, metalloids, or ?

svlad2 [7]

All elements can be classified as metals, metalloids, or nonmetals

5 0

3 years ago

The pre-exponential constant and activation energy for the diffusion of iron in cobalt are 1.7 x 10-5 m2/s and 273,300 J/mol, re

Kitty [74]

<u>Answer:</u> The temperature of the system will be 1622 K

<u>Explanation:</u>

The equation relating the pre-exponential factor and activation energy follows:

$\log D=\log D_o-\frac{E_a}{2.303RT}$

where,

D = diffusion coefficient = $2.7\times 10^{-14}m^2/s$

$D_o$ = pre-exponential constant = $1.7\times 10^{-5}m^2/s$

$E_a$ = activation energy of iron in cobalt = 273,300 J/mol

R = Gas constant = 8.314 J/mol.K

T = temperature = ?

Putting values in above equation, we get:

$\log (2.7\times 10^{-14})=\log (1.7\times 10^{-5})-\frac{273,300}{2.303\times 8.314\times T}\\\\T=1622K$

Hence, the temperature of the system will be 1622 K

8 0

2 years ago