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DedPeter [7]
3 years ago
7

Members of the swim team want to wash their hair. The bathroom has less than 560056005600 liters of water and at most 2.52.52, p

oint, 5 liters of shampoo. 70L+60S < 560070L+60S<560070, L, plus, 60, S, is less than, 5600 represents the number of long-haired members LLL and short-haired members SSS who can wash their hair with less than 560056005600 liters of water. 0.02L+0.01S \leq 2.50.02L+0.01S≤2.50, point, 02, L, plus, 0, point, 01, S, is less than or equal to, 2, point, 5 represents the number of long-haired members and short-haired members who can wash their hair with at most 2.52.52, point, 5 liters of shampoo. Does the bathroom have enough water and shampoo for 888 long-haired members and 777 short-haired members?
Mathematics
1 answer:
juin [17]3 years ago
8 0

Answer:

Yes, both shampoo and water will be enough

Given that:

Number of long and short hair member who can wash their hair ; with amount of water less than 5600 litres

To check if bathroom has enough water and shampoo for 8 long haired and 7 short haired members.

L = long-haired ; S = short-haired

70L+ 60S < 5600

Check the constraint for amount of water :

70L+ 60S < 5600

L = 8 ; S = 7

70(8) + 60(7) < 5600

560 + 420 < 5600

980 < 5600

Constraint satisfied

Number of long and short hair member who can wash their hair with shampoo not more than 2.5 litres

0.02L + 0.01S ≤ 2.5

L = 8 ; S = 7

0.02(8) + 0.01(7) ≤ 2.5

0.16 + 0.07 ≤ 2.5

0.23 ≤ 2.5 (constraint satisfied).

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Answer:

7:1

Step-by-step explanation:

There are two cubes, one with 14 cm and one with 2 cm. 14:2 is equal to 7:1.

4 0
3 years ago
Chick-fil-a found out their most popular items in their combo meals . They found that the Original Chicken Sandwich was ordered
Semenov [28]

Answer:

13/20 probability

Step-by-step explanation:

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7 0
3 years ago
Rename the number 650 in tens
Ad libitum [116K]
Answer (quite straightforward):

650

= 65 x 10
4 0
3 years ago
Read 2 more answers
The length of a 200 square foot rectangular vegetable garden is 4feet less than twice the width. Find the length and width of th
inna [77]

Answer:

Length = 18.099 ft

Width = 11.049 ft

Step-by-step explanation:

let the length of the field be x ft

and the width be y ft

as per the condition given in problem

x=2y-4   -----------(A)

Also the area is given as 200 sqft

Hence

xy=200

Hence from A we get

y(2y-4)=200

taking 2 as GCF out

2y(y-2)=200

Dividing both sides by 2 we get

y(y-2)=100

y^2-2y=100

subtracting 100 from both sides

y^2-2y-100=0

Now we solve the above equation with the help of Quadratic formula which is given in the image attached with this for any equation in form

ax^2+bx+c=0

Here in our case

a=1

b=-1

c=-100

Putting those values in the formula and solving them for y

y=\frac{-(-2)+\sqrt{(-2)^2-4 \times (-1) \times 100}}{2 \time 1}

y=\frac{-(-2)-\sqrt{(-2)^2-4 \times (-1) \times 100}}{2 \time 1}

Solving first

y=\frac{2+\sqrt{4+400}{2}

y=\frac{2+\sqrt{404}{2}

y=\frac{2+20.099}{2}

y=\frac{22.099}{2}

y=11.049

Solving second one

y=\frac{-(-2)-\sqrt{(-2)^2-4 \times (-1) \times 100}}{2 \time 1}

y=\frac{2-\sqrt{4+400}{2}

y=\frac{2-\sqrt{404}{2}

y=\frac{2-20.099}{2}

y=\frac{-18.99}{2}

y=-9.045

Which is wrong as the width can not be in negative

Our width of the field is

y=11.099

Hence the length will be

x=2y-4

x=2(11.049)-4

x=22.099-4

x=18.099

Hence our length x and width y :

Length = 18.099 ft

Width = 11.049 ft

4 0
3 years ago
Which inequalities are true? Select the four correct answers.
tiny-mole [99]

The correct anwer is option C and option E which are √4<√5<√√55 and √8<2.9<√√9.

<h3>What is inequality?</h3>

Inequality is the relationship between two expressions that are not equal, employing a sign such as ≠ “not equal to,” > “greater than,” or < “less than.”.

The two inequalities √4<√5<√√55 and √8<2.9<√√9. are true.

√4<√5<√√55  → 2 < 2.23 < 7.41

√8<2.9<√√9    → 2.82 < 2.9 < 3

Therefore correct answers is option C and option E which are √4<√5<√√55 and √8<2.9<√√9.

To know more about inequality follow

brainly.com/question/24372553

#SPJ1

6 0
2 years ago
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