Answer : The volume of engine in cubic inches is, 
Explanation :
As we are given that the volume of engine is, 7.0 liters. Now we have to calculate the volume of engine in cubic inches.
Conversion used :
So, 
or,
As,
So,
Thu, the volume of engine in cubic inches is,
Answer:
τ ≈ 0.90 N•m
F =
Explanation:
I = ½mR² = ½(10)0.5² = 1.25 kg•m²
α = ω²/2θ = 3.0² / 4π = 0.716... rad/s²
τ = Iα = 1.25(0.716) = 0.8952... ≈ 0.90 N•m
τ = FR
Now we have the unanswered question of reference frame.
80° from what?
If it's 80° from the radial
F = τ/Rsinθ = 0.90/0.5sin80 = 1.818... ≈ 1.8 N
If it's If it's 80° from the tangential
F = τ/Rcosθ = 0.90/0.5cos80 = 10.311... ≈ 10 N
There are an infinite number of other potential solutions
Answer: Option (B) is the correct answer.
Explanation:
It is advised that while conducting an experiment in a laboratory, always perform it under the supervision of your teacher.
When Hiro accidentally touches the liquid then he should immediately tell his teacher about it so that timely precaution can be taken to avoid any damage or side effect. Also, Hiro should rinse his hand in the sink because it will neutralize or decrease the effect of spilled liquid on his skin.
Thus, we can conclude that he should tell his teacher about the spill and rinse his hand in the sink.
Answer:
The magnitude of the truck's velocity relative to the ground is 35.82 m/s.
Explanation:
Given that,
Velocity of car relative to ground = 15.3 m/s
Velocity of truck relative to car = 22.5 m/s
We need to calculate the magnitude of the truck's velocity relative to the ground
We need to calculate the x component of the velocity
We need to calculate the y component of the velocity
Using Pythagorean theorem
Hence, The magnitude of the truck's velocity relative to the ground is 35.82 m/s.
