Answer: I am getting a result around the 54,800 area, so I am selecting the 55,000 HP answer.
For all antinodal positions we know that

now we also know the relation between phase difference and path difference

now we will have

now from above equation we will have

now for the first anti node position
N = 1

Option D is correct
The car acceleration is 22.2 repeating meters per second squared
Answer:
u= 29.43 m/s
h=44.14 m
Explanation:
Given that
t= 3 s
We know that acceleration due to gravity ,g = 9.81 m/s² (Downward)
Initial velocity = u
Final velocity ,v= 0 (At maximum height)
We know v = u +a t
v=final velocity
u=initial velocity
a=Acceleration
Now by putting the values in the above equation
0 = u - 9.81 x 3
u= 29.43 m/s
The maximum height h is given as
v² = u ² - 2 g h
0² = 29.43 ² - 2 x 9.81 x h

h=44.14 m
A charged particle moving in a magnetic field experiences a force equal to:

Thus, the magnitude of the force that the proton experiences is given by:

The magnetic field is perpendicular to the proton's velocity, therefore, we have
. Replacing the given values, we obtain:
