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3 years ago

7

As you change the value of the battery voltage, how does this change the current through the circuit and the resistance of the r

esistor

1 answer:

Lady bird [3.3K]3 years ago

6 0

Answer:

Current increases

Resistance remains same

Explanation:

As you change the value of the battery voltage

We know that the current is dependent on the supply of power , so the current increases but the resistance remains same.

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A ball is launched with an initial velocity of 3m/s, at an angle of 40 degrees above the horizontal, and from a height of 0.5m.

Brut [27]

Answer:

The ball travels <u>1.31 m horizontally</u> before hitting the ground.

Explanation:

Given:

Initial velocity of the ball is, $u=3\ m/s$

Angle of projection is, $\theta=40\ degree$

Initial height of the ball is, $y_0=0.5\ m$

Final height of the ball is, $y=0\ m$

Now, horizontal and vertical components of initial velocity are given as:

$u_x=u\cos\theta\\\\u_y=u\sin\theta$

Plug in the given values and find $u_x\ and\ u_y$ . This gives,

$u_x=3\ m/s\times \cos(40)\\\\u_x=2.3\ m/s\\\\u_y=3\ m/s\times \sin(40)\\\\u_y=1.9\ m/s$

Now, there is acceleration due to gravity acting in the vertical direction. The direction is downward. So, $g=-9.8\ m/s^2$ .

Now, using equation of motion in the vertical direction, we have:

$y-y_0=u_yt+\frac{1}{2}a_y t^2$

Plug in the given values and solve for time 't'. This gives,

$0-0.5=1.9t-0.5\times 9.8\times t^2\\\\-0.5=1.9t-4.9t^2\\\\4.9t^2-1.9t-0.5=0$

On solving the above quadratic equation, we get:

$t=0.57\ s\ or\ t=-0.18\ s$

Ignoring the negative result as time can't be negative. So, time taken by the ball to reach the ground is 0.57 s.

Now, as the ball moves, there is no force acting on it in the horizontal direction. So, the acceleration in the horizontal direction is 0.

Now, we know that, when acceleration is zero, the body moves with a constant speed.

Hence, distance traveled in the horizontal direction is given as:

Horizontal distance = Horizontal component of initial velocity × Time

$R=u_x\times t$

Plug in the given values and solve for 'R'. This gives,

$R=2.3\times 0.57\\\\R=1.31\ m$

So, the ball travels 1.31 m horizontally before hitting the ground.

6 0

3 years ago

The tip of a triangle is held 12.0 cm above the surface of a flat pool of water. A submerged swimmer in the pool sees the tip of

Rufina [12.5K]

Answer: 9cm

Explanation:

Refractive index can also be defined as the ratio of the real depth to the apparent depth.

Given that the

Real depth = 12 m

Refractive index of water = 1.33

Refractive index of air = 1.00

nair/nwater = real depth/apparent depth

Substitute all the parameters into the formula

1.33/1 = 12/ apparent depth

Cross multiply

1.33 Apparent depth = 12

Apparent depth = 12/1.33

Apparent depth = 9.02 cm

Therefore, A submerged swimmer in the pool sees the tip of the triangle at 9cm approximately distance above the water.

8 0

3 years ago

A ball of gas becomes a ____ when nuclear fusion begins in its core.

Ira Lisetskai [31]

The answer to this is Protostar.

This is a process where it is gathering mass from its parent molecular cloud. Its a very young star meaning, the star was now born.

Hope this helped :)
Have a great day

8 0

3 years ago

The convection currents in the asthenosphere cause the movement of the

MA_775_DIABLO [31]

Convection currents generated within the asthenosphere push magma upward through volcanic vents and spreading centres to create new crust. Convection currents also stress the lithosphere above, and the cracking that often results manifests as earthquakes.

7 0

3 years ago

Help plzzzzzzz i need thissssssssss

frutty [35]

Answer:

The final graph

Explanation:

The graph that curves downwards is negative acceleration. While the position decreases the slop increases.

8 0

3 years ago