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kvv77 [185]
3 years ago
15

Victoria is going to invest in an account paying an interest rate of 1.5% compounded quarterly. How much would Victoria need to

invest, to the nearest hundred dollars, for the value of the account to reach $3,300 in 13 years?
Mathematics
1 answer:
mamaluj [8]3 years ago
3 0

Answer: P = 2716.3448786 or about 2700

Step-by-step explanation:

You might be interested in
the half-life of chromium-51 is 38 days. If the sample contained 510 grams. How much would remain after 1 year?​
madam [21]

Answer:

About 0.6548 grams will be remaining.  

Step-by-step explanation:

We can write an exponential function to model the situation. The standard exponential function is:

f(t)=a(r)^t

The original sample contained 510 grams. So, a = 510.

Each half-life, the amount decreases by half. So, r = 1/2.

For t, since one half-life occurs every 38 days, we can substitute t/38 for t, where t is the time in days.

Therefore, our function is:

\displaystyle f(t)=510\Big(\frac{1}{2}\Big)^{t/38}

One year has 365 days.

Therefore, the amount remaining after one year will be:

\displaystyle f(365)=510\Big(\frac{1}{2}\Big)^{365/38}\approx0.6548

About 0.6548 grams will be remaining.  

Alternatively, we can use the standard exponential growth/decay function modeled by:

f(t)=Ce^{kt}

The starting sample is 510. So, C = 510.

After one half-life (38 days), the remaining amount will be 255. Therefore:

255=510e^{38k}

Solving for k:

\displaystyle \frac{1}{2}=e^{38k}\Rightarrow k=\frac{1}{38}\ln\Big(\frac{1}{2}\Big)

Thus, our function is:

f(t)=510e^{t\ln(.5)/38}

Then after one year or 365 days, the amount remaining will be about:

f(365)=510e^{365\ln(.5)/38}\approx 0.6548

5 0
2 years ago
A spacecraft is traveling with a velocity of v0x = 5320 m/s along the +x direction. Two engines are turned on for a time of 739
OlgaM077 [116]

Answer:

The velocities after 739 s of firing of each engine would be 6642.81 m/s in the x direction and 5306.02 in the y direction

Step-by-step explanation:

  1. For a constant acceleration: v_{f}=v_{0}+at, where  v_{f} is the final velocity in a direction after the acceleration is applied, v_{0} is the initial velocity in that direction  before the acceleration is applied, a is the acceleration applied in such direction, and t is the amount of time during where that acceleration was applied.
  2. <em>Then for the x direction</em> it is known that the initial velocity is v_{0x} = 5320 m/s, the acceleration (the applied by the engine) in x direction is a_{x} 1.79 m/s2 and, the time during the acceleration was applied (the time during the engines were fired) of the  is 739 s. Then: v_{fx}=v_{0x}+a_{x}t=5320\frac{m}{s} +1.79\frac{m}{s^{2} }*739s=6642.81\frac{m}{s}
  3. In the same fashion, <em>for the y direction</em>, the initial velocity is  v_{0y} = 0 m/s, the acceleration in y direction is a_{y} 7.18 m/s2, and the time is the same that in the x direction, 739 s, then for the final velocity in the y direction: v_{fy}=v_{0y}+a_{y}t=0\frac{m}{s} +7.18\frac{m}{s^{2} }*739s=5306.02\frac{m}{s}
8 0
3 years ago
Which equation describes the line that passes through the points (-4, 19) and (2, -1)
dangina [55]

Answer:

y=-5/2x+4

Step-by-step explanation:

find the slope by using y2-y1/x2-x1

-1-19/2-(-4)

simplify

-20/8

simplify

-5/2

use slope-intercept form, y=mx+b

since we know the slope, find b

plug in one of the ordered pairs into the equation

-1=(-5/2)(2)+b

simplify

-1= -10/2+b

simplify

-1=-5+b

add 5 to both sides

b=4

plug b into y=-5/2x+b

y=-5/2x+4

8 0
2 years ago
Read 2 more answers
Factor completely 5ax2 − 20x3 + 2a − 8x.
Viefleur [7K]

Answer:

C

Step-by-step explanation:

5ax²-20x³+2a-8x

=5 x²(a-4x)+2(a-4x)

=(a-4x)(5x²+2)

3 0
3 years ago
Read 2 more answers
QuestiuI4
4vir4ik [10]

Answer:

The new volume is 14,850cm³

Step-by-step explanation:

Given

Volume of a rectangular prism = 550cm

Required

Value of volume when the dimensions are tripled.

The volume of a rectangular prism is calculated using the following formula.

V = lbh

<em>When Volume = 550, the formula is written as follows</em>

550 = lbh

<em>Rearrange</em>

lbh = 550

However, when each dimension is tripled.

This means that,

new length = 3 * old length

new breadth = 3 * old breadth

new height = 3 * old height

<em>Let L, B and H represent the new length, new breadth and new height respectively</em>

In other words,

L = 3l

B = 3b

H = 3h

Calculating new volume

New volume = LBH

Substitute, 3l for L, 3b for B and 3h for H;

V = 3l * 3b * 3h

V = 3 * l * 3 * b * 3 * h

V = 3 * 3 * 3 * l*b*h

V = 27 * lbh

Recall that lbh = 550

So,

V = 27 * 550

V = 14,850

Hence, the new volume is 14,850cm³

6 0
3 years ago
Read 2 more answers
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