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eimsori [14]
3 years ago
9

Which of the following shows a coefficient?

Chemistry
1 answer:
rosijanka [135]3 years ago
6 0

Answer:

my answer is b oti d I am not sure

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Which of the following statements correctly relates mutations and survival rates of plants?
Tasya [4]
Answer is: <span>Mutations sometimes improve the chances of survival for a plant.
</span>Mutations are very important because they change <span>variability in populations and in that way enable evolutionary change.
</span>There are three types of mutations:
1) good or advantageous mutations - <span> improve the chances of survival for a plant.
2) </span>bad or deleterious - decrease the chances of survival for a plant.
3) neutral -  not affect he chances of survival for a plant.
3 0
4 years ago
Find the empirical and molecular formula for a molar mass of 60.10g/mol; 39.97% carbon 13.41% hydrogen: 46.62% nitrogen
PSYCHO15rus [73]
Assuming we have 100g, this means that

39.97g Carbon * 1 mol / 12 g = 3.33 mol Carbon
13.41g Hydrogen * 1 mol/1 g = 13.41 mol Hydrogen
46.62g Nitrogen * 1 mol / 14 g = 3.33 mol Nitrogen
Dividing everything by 3.33, we get

1 mol Carbon, 4.03 mol Hydrogen, 1 mol Nitrogen.

Empirical formula is CH4N

<span>The mass of the empirical formula is
12 + 4 + 14 = 30

Since the molar mass is double, we multiply all our subscripts

The molecular formula is C2H8N2

The answers to this question are </span><span>an empirical formula of CH4N</span> and a molecular formula of C2H8N2 .
5 0
3 years ago
A mineral forms in water heated by magma inside Earth.
allsm [11]

Answer:

the mineral formed when a hot water solution cooled

4 0
3 years ago
Read 2 more answers
At −15.0 ∘C , a common temperature for household freezers, what is the maximum mass of sucrose (C12H22O11) you can add to 1.50 k
nlexa [21]

Answer: The maximum mass of sucrose you can add is 4158.95 grams.

Explanation:

This is an example of freezing point depression. The formula for calculating this is the following:

ΔT = Kf . b . i

ΔT is the temperature depression

Kf is the cryoscopic constant that is unique for each solvent

b is the molality of the solution (moles of solute per kg of solvent)

i is the Vant Hoff factor

The freezing point of water is 0°C. ΔT equals inicial temperature - final temperature, so it's 0°- (-15°)= 273K - 258K = 15K

The Kf for water is known to be 1.853 K. Kg /mol

i is the number of particles the molecule is split to when ionized. Because sucrose doesn't ionize, its Vant Hoff factor is 1.

If we clear b from the ecuation:

b = ΔT/ Kf . i

b = 15K/ 1.853 K. Kg/mol . 1

b= 8.1 mol/kg

If we can add 8.1 moles to a kg of water before it freezes, we use cross multiplication to calculate how many we can add to 1.5 kg. The answer is 12.15.

The weight of a mole of sucrose is 342.3 grams. So the weight of 12.15 moles of sucrose is 4158.95g.

3 0
3 years ago
0.50 mol A, 0.60 mol B, and 0.90 mol C are reacted according to the following reaction
algol [13]

Reactant C is the limiting reactant in this scenario.

Explanation:

The reactant in the balanced chemical reaction which gives the smaller amount or moles of product is the limiting reagent.

Balanced chemical reaction is:

A + 2B + 3C → 2D + E

number of moles

A = 0.50 mole

B = 0.60 moles

C = 0.90 moles

Taking A as the reactant

1 mole of A reacted to form 2 moles of D

0.50 moles of A will produce \frac{2}{1} = \frac{x}{0.50}

thus 0.50 moles of A will produce 1 mole of D

Taking B as the reactant

2 moles of B reacted to form 2 moles of D

0.60 moles of B reacted to form x moles of D

\frac{2}{2} = \frac{x}{0.6}

x = 2 moles of D is produced.

Taking C as the reactant:

3 moles of C reacted to form 2 moles of D

O.9 moles of C reacted to form x moles of D

\frac{2}{3} = \frac{x}{0.9}

= 0.60 moles of D is formed.

Thus C is the limiting reagent in the given reaction as it produces smallest mass of product.

5 0
3 years ago
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