First, we need to calculate the molar mass of the whole compound by adding the masses of each atom from the periodic table.
Mg= 24.3 g/mol
Br= 80.0 g/mol
molar mass MgBr2= 24.3 + 2 x 80.0= 184.3 g/mol
to find the percent of magnesium doing "parts over the whole"
the mass of magnesium over the total mass. then times 100 because it is a percentage value
24.3/184.3x 100= 13.2%
The % yield if 200g of chlorine react with excess Potassium bromide to produce 410g of bromine is calculated as below
% yield = actual yield/theoretical yield x100
the actual yield = 410 grams
calculate the theoretical yield
by first calculate the moles of chlorine used
mole= mass/molar mass
molar mass of Cl2 = 35.5 x2= 71 g/mol
moles= 200g/71g/mol = 2.82 moles
cl2 +2 KBr = 2KCl +Br2
by use of mole ratio between Cl2 to Br2 which is 1:1 the moles of Br2 is also = 2.82 moles
theoretical mass = moles x molar mass
molar mass of Br2= 79.9 x2= 159.8 g/mol
moles= 2.82g x 159.8 g/mol = 450.64 grams
% yield is therefore = 410g/450.64 x100 = 90.98 %
translate please I'm confused
Explanation:
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Answer:
The more polar bond is C-O.
Explanation:
The greater polarity is due to that the Oxygen atom is more electronegative than the Nitrogen atom, so the negativity of the molecule tends to be on that side.
