the percent yield of the reaction is 100%.
The percent yield is calculated as the experimental yield divided by the theoretical yield x 100%:
% yield = actual yield / theoretical yield * 100%
% yield of a reaction in this case Rate
In this case, the molar mass of NaBr is 102.9 g / mol, as you know:
444 actual yield = 7.08 mol x 102.9 g / mol = 728.532 g
theoretical yield = 7.08 mol x 102.9 g / mol = 728.532 g
, Replaced by the definition of percent yield:
percent yield = 728.532 grams / 728.532 grams * 100%
percent yield = 100%
Finally, the percent yield of the reaction is 100%.
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FeBr3 is iron bromide. Also known as iron bromide. Iron bromide is an ionic compound in which iron is in a +3 oxidation state.
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Answer:
hunting for other animals or when they are really hungry
Explanation:
To determine the number of moles of the gas, we need to relate moles to pressure, temperature and volume. To simplify things, we assume the gas is ideal so we use the ideal gas equation PV=nRT.
PV = nRT
n = PV / RT
n = 3.5 (9.0) / 0.08205 (74+273.15)
n = 1.1059 mol
Best Answer: <span> Moles of O2 =3.01 x 10^23 / 6.02 x 10^23 = 0.500
mass O2 = 0.500 mol x 32 g/mol= 16 g </span>
The answer is B. s, p, d, f
