A car travels 150 meters East of its original starting position in 15s. What is the cars velocity?
2 answers:
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Answer:
The net force acting on this object is 180.89 N.
Explanation:
Given that,
Mass = 3.00 kg
Coordinate of position of
Coordinate of position of
Time = 2.00 s
We need to calculate the acceleration
For x coordinates
On differentiate w.r.to t
On differentiate again w.r.to t
The acceleration in x axis at 2 sec
For y coordinates
On differentiate w.r.to t
On differentiate again w.r.to t
The acceleration in y axis at 2 sec
The acceleration is
We need to calculate the net force
The magnitude of the force
Hence, The net force acting on this object is 180.89 N.
Answer with Explanation:
We are given that
Speed ,=107257 kmph
Angular velocity,
Radius of earth,r=
1 km=1000 m
Linear velocity,
Linear velocity,
Velocity at point A,
Velocity at point B,
Velocity at point C,
Velocity at point D,