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Alina [70]
3 years ago
5

What would a series circuit be used for?

Physics
1 answer:
igor_vitrenko [27]3 years ago
6 0

Answer:

C

Explanation:

a series circuit would be an odd choice to power a battery or light a lamp when a direct would be much more efficient, and it's not converting types of energy, so C is the best possible answer

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Water waves in a small tank are .06 m long. They pass a given point at a rate of 14.8 waves every three seconds. What is the spe
snow_lady [41]

Answer:

Speed = 0.296m/2

Period = 0.203 s

Explanation:

If by 'long' you mean the wavelength of the waves, then the wavelength \lambda=0.06m.

The frequency f of the waves is 14.8 waves every 3 seconds or

f=14.8/3 =4.33Hz.

Now the relationship between wavelength \lambda, frequency f and speed v of the waves is:

v=\lambda f

We put in the values \lambda=0.06m and f=4.933Hz and get:

\boxed{v=0.06*4.922=0.296m/s}

Now the period T is just the inverse of the frequency, or

T=\frac{1}{f}

\boxed{T=\frac{1}{4.933}=0.203\:seconds }

4 0
3 years ago
If the absolute temperature of a gas is 600 K, the temperature in degrees Celsius is: A. 705°C. B. 873°C. C. 273°C. D. 327°C
zlopas [31]

Answer:

D). 327 ^0 C

Explanation:

As we know that temperature scale is linear so we will have

\frac{^0C - 0}{100 - 0} = \frac{K - 273}{373 - 273}

now we have

\frac{^0 C - 0}{100} = \frac{K - 273}{100}

so the relation between two scales is given as

^0 C = K - 273

now we know that in kelvin scale the absolute temperature is 600 K

so now we have

T = 600 - 273 = 327 ^0 C

so correct answer is

D). 327 ^0 C

4 0
3 years ago
A stuntwoman is going to attempt a jump across a canyon that is 77 m wide. The ramp on the far side of the canyon is 25 m lower
liq [111]

initial speed of the stuntman is given as

v = 28 m/s

angle of inclination is given as

\theta = 15 degree

now the components of the velocity is given as

v_x = 28 cos15 = 27.04 m/s

v_y = 28 sin15 = 7.25 m/s

here it is given that the ramp on the far side of the canyon is 25 m lower than the ramp from which she will leave.

So the displacement in vertical direction is given as

\delta y = -25 m

\delta y = v_y * t + \frac{1}{2} at^2

-25 = 7.25 * t - \frac{1}{2}*9.8* t^2

by solving above equation we have

t = 3.12 s

Now in the above interval of time the horizontal distance moved by it is given by

d_x = v_x * t

d_x = 27.04 * 3.12 = 84.4 m

since the canyon width is 77 m which is less than the horizontal distance covered by the stuntman so here we can say that stuntman will cross the canyon.

5 0
3 years ago
А man runs 20 km west is hows. He then runs 20km 60° north or west 2.5 hours. what's the average velocity the Runnner?​
shepuryov [24]

Explanation:

\large{ \star \fcolorbox{magenta}{purple}{ \fcolorbox{magenta}{blue}{ \fcolorbox{magenta}{pink}{ \fcolorbox{magenta}{red}{ \sf{ añswër}}}}}} \star

<h2>8km/h</h2>
7 0
2 years ago
Using hooke's law find the elastic constant of a spring that stretches 2 cm when 4newton force is applied to it
Kay [80]

<u>Answer:</u>

2N/cm

<u>Step-by-step explanation:</u>

According to the Hooke's Law, the force required to extend or compress a spring is directly proportional distance you can stretch it, which is represented as:

F=kx

where, F is the force which is stretching or compressing the spring,

k is the spring constant; and

x is the distance the spring is stretched.

Substituting the given values to find the elastic constant  k to get:

F=kx

4=k(2)

k=\frac{4}{2}

k=2

Therefore, the elastic constant is 2 Newton/cm.

3 0
3 years ago
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