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3 years ago

URGENT I WILL GIVE BRAINLIEST

Physics

1 answer:

Reil [10]3 years ago

4 0

Weight : It is the gravitational attraction force on an object near its surface.

It is always measured in the unit of Newton(N)

it is given by the product of mass and acceleration due to gravity

$W = mg$

here we know that mass of the pig is m = 140 kg

also we know that acceleration due to gravity near the surface of earth is approximately g = 9.8 m/s/s

so here we know by above formula

$W = (140 kg)(9.8 m/s^2)$

$W = 1372 N$

so correct answer will be

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A string under a tension of 68 N is used to whirl a rock in a horizontal circle of radius 3.7 m at a speed of 16.53 m/s. The str

alekssr [168]

Answer:

$F = 5253.7 N$

Explanation:

As we know that tension force in the string will be equal to the centripetal force on the string

so we will have

$T = \frac{mv^2}{L}$

now we have

$68 = \frac{m(16.53^2)}{3.7}$

now we have

$68 = 73.8 m$

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now when string length is 0.896 m and its speed is 71.5 m/s then we will have

$F = \frac{mv^2}{r}$

$F = \frac{0.92(71.5^2)}{0.896}$

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An object is thrown vertically and has an upward velocity of 18 m/s when it reaches one fourth of its maximum height above its l

Murrr4er [49]

Answer:

v = 25.45 m/s

Explanation:

In order to calculate the initial speed of the object, you take into account the formula for the maximum height reaches by the object. Such a formula is given by:

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vo: initial speed of the object = 18 m/s

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Furthermore you use the following formula for the final speed of the object:

$v^2=v_o^2-2gh$ (2)

h: height

You know that the speed of the object is 18m/s when it reaches one fourth of the maximum height. You use this information, and you replace the equation (1) in to the equation (2), as follow:

$v^2=v_o^2-2g(\frac{h_{max}}{4})=v_o^2-\frac{1}{2}g(\frac{v_o^2}{g})\\\\v^2=v_o^2-\frac{1}{2}v_o^2=\frac{1}{2}v_o^2$

Then, you solve the previous result for vo:

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The initial speed of the object was 25.45 m/s

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