I think the answer to your question may be C.)
I'd suggest using "elimination by addition and subtraction" here, altho' there are other approaches (such as matrices, substitution, etc.).
Note that if you add the 3rd equation to the second, the x terms cancel out, and you are left with the system
- y + 3z = -2
y + z = -2
-----------------
4z = -4, so z = -1.
Next, multiply the 3rd equation by 2: You'll get -2x + 2y + 2z = -2.
Add this result to the first equation. The 2x terms will cancel, leaving you with the system
2y + 2z = -2
y + z = 4
This would be a good time to subst. -1 for z. We then get:
-2y - 2 = -2. Then y must be 0. y = 0.
Now subst. -1 for z and 0 for y in any of the original equations.
For example, x - (-1) + 3(0) = -2, so x + 1 = -2, or x = -3.
Then a tentative solution is (-3, -1, 0).
It's very important that you ensure that this satisfies all 3 of the originale quations.
Answer:
Step-by-step explanation:
Given
Jar contains 4 white and 4 black marbles
We randomly select 4 marbles out of which 2 are white and 2 are black
Probability that 2 white and 2 black marbles are selected is
The process is continue for n trails until we choose the correct order
i.e. we have to fail in n-1 trails
For exact n selection Probability is given by
Answer:
because all the fans have left
Step-by-step explanation:
You put the whole number on top of 1, it doesnt change its value. then you simplify across like in a butterfly only if needed then you multiply across from left to right.
