Answer:
The pressure is 5.62 atm.
Explanation:
An ideal gas is a theoretical gas that is considered to be composed of randomly moving point particles that do not interact with each other. Gases in general are ideal when they are at high temperatures and low pressures.
An ideal gas is characterized by three state variables: absolute pressure (P), volume (V), and absolute temperature (T). The relationship between them constitutes the ideal gas law, an equation that relates the three variables if the amount of substance, number of moles n, remains constant and where R is the molar constant of the gases:
P * V = n * R * T
In this case:
- P= ?
- V= 5.005 L
- n= 1.255 mol
- R= 0.082
![\frac{atm*L}{mol*K}](https://tex.z-dn.net/?f=%5Cfrac%7Batm%2AL%7D%7Bmol%2AK%7D)
- T= 273.5 K
Replacing:
P* 5.005 L= 1.255 mol* 0.082
*273.5 K
Solving:
![P=\frac{1.255 mol* 0.082 \frac{atm*L}{mol*K} *273.5 K}{5.005 L}](https://tex.z-dn.net/?f=P%3D%5Cfrac%7B1.255%20mol%2A%200.082%20%5Cfrac%7Batm%2AL%7D%7Bmol%2AK%7D%20%2A273.5%20K%7D%7B5.005%20L%7D)
P= 5.62 atm
<u><em>The pressure is 5.62 atm.</em></u>
Answer : The correct expression for equilibrium constant will be, ![K=[KOH]^2[H_2]](https://tex.z-dn.net/?f=K%3D%5BKOH%5D%5E2%5BH_2%5D)
Explanation :
Equilibrium constant : It is defined as the equilibrium constant. It is defined as the ratio of concentration of products to the concentration of reactants.
The equilibrium expression for the reaction is determined by multiplying the concentrations of products and divided by the concentrations of the reactants and each concentration is raised to the power that is equal to the coefficient in the balanced reaction.
As we know that the concentrations of pure solids and liquids are constant that is they do not change. Thus, they are not included in the equilibrium expression.
The given equilibrium reaction is,
![2K(s)+2H_2O(l)\rightleftharpoons 2KOH(aq)+H_2(g)](https://tex.z-dn.net/?f=2K%28s%29%2B2H_2O%28l%29%5Crightleftharpoons%202KOH%28aq%29%2BH_2%28g%29)
The expression of
will be,
![K=[KOH]^2[H_2]](https://tex.z-dn.net/?f=K%3D%5BKOH%5D%5E2%5BH_2%5D)
Therefore, the correct expression for equilibrium constant will be, ![K=[KOH]^2[H_2]](https://tex.z-dn.net/?f=K%3D%5BKOH%5D%5E2%5BH_2%5D)
Answer:
Explain your answer. mg2+ would be the smaller ion this is because each ion has the same number of electrons however mg2+ has a greater number of protons and therefore is more charge dense and the outer electrons feel a greater pull from the nucleus.
Hope this helps, have a great day/night, and stay safe!
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