Answer:
Fist column, apply the density of water.
Second column is material density, so it's mass of sample / volume of sample
Explanation:
Water density is 1 g/mL
Mass / Volume
If you have 0.25 g, 0.45g and 0.46 g of water, then you have the same values as volume, 0.25mL, 0.45mL and 0.46mL.
Again, density is the relation mass / volume so:
2.20 g / 0.25mL
3.73 g / 0.46 mL
3.52 g / 0.45mL
<u>Answer:</u> The correct answer is Option C.
<u>Explanation:</u>
To calculate the number of moles, we use the equation:

Given mass of methane = 48.2 g
Molar mass of methane = 16 g/mol
Putting values in above equation, we get:

According to mole concept:
1 mole of compound contains
number of molecules.
So, 3.0125 moles of methane will contain =
number of molecules.
Hence, the correct answer is Option C.
Answer:
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Explanation:
The equation is one to one so you can use M1V1=M2V2
so
(30ml)(.10M)=(25ml)(x)
x= .12M
Answer:
Possible lowest volume = 0.19 cm
Possible highest volume = 0.21 cm
Explanation:
Given Data
uncertainty = 0.01 cm
total volume = 0.20 cm
Possible lowest volume = ?
Possible highest volume = ?
Solution:
Possible lowest volume = total volume - uncertainty
Possible lowest volume = 0.20 cm - 0.01 cm
Possible lowest volume = 0.19 cm
Possible highest volume = total volume + uncertainty
Possible highest volume = 0.20 cm - 0.01 cm
Possible highest volume = 0.21 cm