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bogdanovich [222]
3 years ago
11

A student fires a cannonball diagonally

Physics
1 answer:
rodikova [14]3 years ago
8 0

Answer:The cannons total flight time is 2.23seconds

Explanation:

A ball fired diagonally is fired at an angle of 45° to the horizontal. The motion of the fired ball is a projectile motion. A projectile is a motion in which an object fired into space with an initial velocity U is allowed to fall freely under the influence of gravitational force.

To total time of flight T of the cannon ball can be expressed as;

T = 2Usin(theta)/g where;

U is the initial velocity or speed of the ball = 31m/s

theta is the angle that the ball make with the horizontal = 45°

g is the acceleration due to gravity = 9.81m/s²

Substituting the given datas into the formula we have;

T = 31sin45°/9.81

T = 31×0.7071/9.81

T = 21.92/9.81

T = 2.23seconds

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I_r=2\times10^4I_d=2\times10^4\times10^{5.9}I_o

I_r(dB)=10log\frac{I_r}{I_o}\\=10log\frac{2\times 10^{9.9}I_o}{I_o}=10\times10.2\\=102 dB

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What happens to particles in a surface wave (such as a water wave)?
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1. Dos puntos A y B están separados en línea recta 1475 m. Por el punto A pasa hacia el punto B un móvil con una velocidad de 15
ikadub [295]

Answer:

a) 35 sequndos   b) M1 = 600m   M2 = 875m

Explanation:

a)

Antes de que el otro móvil comience a moverse, el primer móvil ha viajado 5 segundos a una velocidad de 15 m / s.

5 segundos x 15 m / s = 75 metros.

Podemos establecer una ecuación con la información que conocemos. Juntos, en total, los dos recorren 1475 metros.

Voy a representar el tiempo como t. Un móvil ya ha recorrido 75 metros y hará otros 15 t. El otro aún no se ha movido y viajará 25t. Esos tres números se sumarán a 1475.

75 + 15t + 25t = 1475.

Resta 75 de ambos lados y suma términos similares de t: 40t = 1400

t = 35 segundos.

b)

Ahora tome la distancia recorrida por cada vehículo por separado y conecte 35 segundos para t.

Primer móvil: 75 + 15t = 75 + 15 (35) = 600m

Segundo móvil: 25t = 25 (35) = 875m

Usé un traductor para entender la pregunta y luego traduje lo que escribí. Lo siento si mi explicación no es clara.

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