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Sunny_sXe [5.5K]
3 years ago
5

On a sunny day, as the distance from your hand to the ground increases, the shadow of your hand on the ground become fuzzier bec

ause:
Physics
1 answer:
USPshnik [31]3 years ago
4 0

Answer:

the Sun is a circle in the sky and that creates a penumbra

Explanation:

A penumbra is basically a lighter and hazy outer part of the shadow. It is the partially shaded portion of the outer region of a shadow that is cast by an opaque object.

In the context, as the distance from the hand to the surface of the ground increases on a sunny day, the shadow of the hand that falls on the ground becomes fuzzier because the sun is an opaque object in the sky and it creates a penumbra which makes the shadow of the hand on the ground fuzzier as the distance is increased.

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in coal-fired power plants, coal is burned to produce ____________________, which is then used to turn a turbine.
crimeas [40]
The answer is STEAM.
6 0
3 years ago
Read 2 more answers
Bats are capable of navigating using the earth's field-a plus for an animal that may fly great distances from its roost at night
Nataliya [291]

Answer:

The correct magnitude of the coil's magnetic field= =50μT

Explanation :

The magnetic field takes place as a result of movement of charge I e current, can also occurs from magnetised material, magnetic field as a result of charge movement can be deducted using right hand grip rule.

At the equator magnetic field lines are parallel towards the earth's surface and the angle of inclination of the magnetic lines of force at the horizontal position is referred to as the angle of dip at the point.

As the current is produced then the varying magnetic field is opposed ,then there is induced current when the coil is positioned at varying magnetic field.

Given from the question,

angle below horizontal θ=60-degree

The Earth's magnetic field B=50μT

The horizontal magnetic field can be expressed in terms of the formula below;

BH=Bcos⁡θ

B(H) = earth's horizontal component of magnetic field

Ø is the angle between coil's field

B=the magnetic field in Tesla

Then,

BH=50μT×cos60∘

=50μT× 0.5

As the current is passed through the coil to produce a field , when combined with the earth's field, which creates a net field with the same strength and dip angle (60 degrees below horizontal) as the earth's field.

It can be deducted that B has the same magnitude and angle which makes the those vertical component to cancel each other since they are the same.

For the magnetic field to be pointed out at North direction, we can calculate the corrected magnetic field using the formula below

Bc=2BH

Bc=2×50μT× 0.5=50μT

The correct magnitude of the coil's magnetic field= =50μT

4 0
4 years ago
a 4lb ball is travelling in a circle radius 3ft speed 6ft/s. the attached cord pulled through the center has constant speed 2ft/
lora16 [44]

Answer:

Explanation:

Circle motion

Weight=4lb

Radius=3ft

Velocity Vb= 6ft/s

Velocity Vr=2ft/s

Velocity Vo=12

V2=√Vo²+Vr²

12=√Vo²+2²

Square both side

144=Vo²+4

Vo²=140

Vo=11.83ft/s

Applying conservation of angular momentum

Ha1=Hb2

MbVbr1=MbVor2

r2=Vbr1/Vo

r2=6×3/11.83

r2=1.52ft

The require time is written as.

∆r=Vrt

t=∆r/Vr

t=r1-r2/Vr

t=3-1.52/2

t=0.74sec

4 0
4 years ago
The drawing shows a model for the motion of the human forearm in throwing a dart. Because of the force M applied by the triceps
Serga [27]

Answer:

464.3 N

Explanation:

Given parameters are:

I = 0.065 kg*m^2

L = 0.025 m

R = 0.28 m

v_0 = 0 m/s

v_f = 5 m/s

t = 0.1 s

v_f=v_0+at=at

Hence, a=v_f/t

We must connect two torque equations to find the answer.

\tau=LM=I\alpha

Where \alpha =\frac{a}{R} =\frac{v_f}{Rt}

Hence, LM=I\frac{v_f}{Rt}

Thus, M = \frac{Iv_f}{LRt} = \frac{0.065*5}{0.025*0.28*0.1} =464.3 N

5 0
4 years ago
A 3-ton Toyota land cruiser travelled at a speed of 45m/s, collides with a 2- ton comfort taxi which was parked in front of the
Olin [163]

Answer:

v = 27 m/s

Explanation:

To find the speed of cars after the collision  you take into account the momentum conservation law. Total momentum of both cars before the collision must be equal to the total momentum of both cars after the collision.

After the collision both cars traveled together, then you have:

m_1v_1+m_2v_2=(m_1+m_2)v   (1)

m1: mass of the Toyota = 3-ton = 3000 kg

m2: mass of the taxi = 2-ton = 2000kg

v1: speed of the Toyota before the collision = 45m/s

v2: speed of the car before the collision = 0 m/s (it is  at rest)

v: speed of both cars after the collision = ?

You solve the equation (1) for v:

v=\frac{m_1v_1+m_2v_2}{m_1+m_2}

Next, you replace the values of the rest of the variables:

v=\frac{(3000kg)(45m/s)+0kgm/s}{3000kg+2000kg}=27\frac{m}{s}

hence, just after the collision both cars have a speed of 27m/s

7 0
3 years ago
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