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3 years ago

Hahsusiaianbaisisii jsusis

Chemistry

2 answers:

photoshop1234 [79]3 years ago

7 0

Answer:

yes i understand

Explanation:

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astra-53 [7]3 years ago

3 0

Bob idvoebpapalbksfugdb

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A solution was prepared by dissolving 2.2 g of an unknown solute in 16.7 g of CCl4. A thermal analysis was performed for this so

laila [671]

Answer:

Molar mass of unknown solute is 679 g/mol

Explanation:

Let us assume that the solute is a non-electrolyte.

For a solution with non-electrolyte solute remains dissolved in it -

Depression in freezing point of solution, $\Delta T_{f}=K_{f}.m$

where, m is molality of solute in solution and $K_{f}$ is cryogenoscopic constant of solvent.

Here $\Delta T_{f}=(-22.9^{0}\textrm{C})-(-28.7^{0}\textrm{C})=5.8^{0}\textrm{C}$

If molar mass of unknown solute is M g/mol then-

$m=\frac{\frac{2.2}{M}}{0.0167}mol/kg$

So, $5.8^{0}\textrm{C}=29.9^{0}\textrm{C}/(mol/kg)\times \frac{\frac{2.2g}{M}}{0.0167}mol/kg$

so, M = 679 g/mol

4 0

3 years ago

3. When the hydronium ion concentration of a solution is 1x10-4 M, What

rewona [7]

Answer:

pH = 4

Solution is acidic

Explanation:

Given data;

Hydronium ion concentration = 1 × 10⁻⁴ M

pH of solution = ?

Solution:

pH = -log [H₃O⁺]

pH = -log [ 1 × 10⁻⁴ ]

pH = 4

According to pH scale the pH 7 is neutral while the pH less than 7 is acidic and greater than 7 is basic. The given solution has pH 4 it means solution is acidic.

7 0

3 years ago

Someone pls help me With this I will make you as brain

RoseWind [281]

The answer to that question is c

5 0

3 years ago

When a car engine burns gasoline, the results of the reaction are similar to when cells burn glucose. both reactions release car

-Dominant- [34]

the answer is heat. while a car is in idol, the tailpipe gets very hot, (motorcycle, car, etc.) this also produces h20 which you can see dripping out of the tailpipe.

3 0

4 years ago

A 2.684-g sample of zinc oxide was reduced by hydrogen gas, resulting in 2. 156 g of pure zinc metal. Determine the empirical fo

Afina-wow [57]

The empirical formula of the initial zinc oxide is ZnO.

<h3>What is Empirical Formula?</h3>

The empirical formula of a compound represents the ratios of elements in a compound but not the actual numbers or arrangement of the atoms.

It is the lowest whole number ratio of the element in the compound.

<h3>How to find out the empirical formula?</h3>

Find out the given masses and molar masses of the elements

The molar mass of Zn = 65 gmol⁻¹

Given the mass of Zn = 2.156 g

The molar mass of Oxygen = 16 gmol⁻¹

The mass of Oxygen = Mass of a sample of zinc oxide - the mass of zinc metal

= (2.684 - 2.156) g

= 0.528 g

Find the number of moles of the elements in the compound

The number of moles is given by

$n = \frac{m}{M}$

where m = given mass and

M = Molar mass

Number of moles of Zinc = $\frac{2.156}{65}$ = 0.033 moles

Number of moles of Oxygen = $\frac{0.528}{16}$ = 0.033 moles

Find the simplest ratios of the elements in the compound. To find the ratios simply divide the number of moles by the lowest number of moles obtained.

Here, the number of moles is the same for both elements. Hence, the simplest ratio for Zn:O is 1:1.

Therefore, the empirical formula of zinc oxide is ZnO.

Learn more about the empirical formula:

brainly.com/question/1603500

#SPJ4

5 0

1 year ago