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dalvyx [7]
3 years ago
9

What is the weight of a 5 inch solid circular bar with a one inch diameter if the density weight of gold is .698 Ibs/in^3?

Engineering
1 answer:
Mandarinka [93]3 years ago
7 0
It appears that the answer is C
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Answer:

(a) 3.185*10^{21} cells

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Explanation:

(a)

Volume, V of unit cell

V=(2.866*10^{-8})^{3}=2.354*10^{-23}

Number of unit cells, N

N=\frac {W_{mat}}{V\rho_{mat}} Where W_{mat} is weight of material and \rho_{mat} is density of material

N=\frac{0.59}{7.87*(2.354*10^{-23}}=3.185*10^{21} cells

(b)

Number of atoms in paper clip

This is a product of number of unit cells and number of atoms per cell

Since iron has 2 atoms per cell

Number of atoms of iron=3.185*10^{21} cells*2 atoms/cell=6.37*10^{21} atoms

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