The expression of V(m³)=e^(t(s)) to make V in in³ and t in minutes is;
V(in³) = (¹/₆₁₀₂₄)a
We are given that;
Volume of microbial culture is observed to increase according to the formula;
V = e^(t)
where;
t is in seconds
V is in m³
We want to now express V in in³ and t in minutes.
Now, from conversions;
1 m³ = 61024 in³
Also; 1 second = 1/60 minutes
according to formula for exponential decay, we know that;
V = ae^(bt)
Thus, we have;
61024V = ae^(¹/₆₀b(t(h))
V(in³) = (¹/₆₁₀₂₄)a
Read more about subject of formula at; brainly.com/question/790938
Answer:
appropriate tunnel pressure is 384.64 ATM
Even at this (high) pressure, exact dynamic similarity is not achieved because the specific heat ratio of helium is approximately 1.66 and is not equal to that of air which is approximately 1.40
Explanation:
It is too long to type here.
Kindly check the attached file for the calculation.
Answer:
0.19s
Explanation:
Queueing delay is the time a job waits in a queue before it can be executed. it is the difference in time betwen when the packet data reaches it destination and the time when it was executed.
Queueing delay =(N-1) L /2R
where N = no of packet =93
L = size of packet = 4MB
R = bandwidth = 1.4Gbps = 1×10⁹ bps
4 MB = 4194304 Bytes
(93 - 1)4194304 / 2× 10⁹
queueing delay =192937984 ×10⁻⁹
=0.19s