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natita [175]
3 years ago
8

2. A F-22 Raptor has just climbed through an altitude of 9,874 m at 1,567 kph when a disk

Engineering
1 answer:
BabaBlast [244]3 years ago
3 0

The pressure difference across the sensor housing will be "95 kPa".

According to the question, the values are:

Altitude,

  • 9874

Speed,

  • 1567 kph

Pressure,

  • 122 kPa

The temperature will be:

→ T = 15.04-[0.00649(9874)]

→     = 15.04-64.082

→     = -49.042^{\circ} C

now,

→ P_o = 101.29[\frac{(-49.042+273.1)}{288.08} ]^{(5.256)}

→      = 27.074

hence,

→ The pressure differential will be:

= 122-27

= 95 \ kPa

Thus the above solution is correct.

Learn more about pressure difference here:

brainly.com/question/15732832

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IN JAVA,
Citrus2011 [14]

Answer:

Explanation:

Code:

import java.io.File;

import java.io.FileWriter;

import java.io.IOException;

import java.util.Scanner;

public class Knapsack {

 

  public static void knapsack(int wk[], int pr[], int W, String ofile) throws IOException

  {

      int i, w;

      int[][] Ksack = new int[wk.length + 1][W + 1];

     

      for (i = 0; i <= wk.length; i++) {

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  Ksack[i][w] = Math.max(pr[i - 1] + Ksack[i - 1][w - wk[i - 1]], Ksack[i - 1][w]);

  else

  Ksack[i][w] = Ksack[i - 1][w];

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      int maxProfit = Ksack[wk.length][W];

      int tempProfit = maxProfit;

      int count = 0;

      w = W;

      int[] projectIncluded = new int[1000];

      for (i = wk.length; i > 0 && tempProfit > 0; i--) {

         

      if (tempProfit == Ksack[i - 1][w])

      continue;    

      else {

          projectIncluded[count++] = i-1;

      tempProfit = tempProfit - pr[i - 1];

      w = w - wk[i - 1];

      }

     

      FileWriter f =new FileWriter("C:\\Users\\gshubhita\\Desktop\\"+ ofile);

      f.write("Number of projects available: "+ wk.length+ "\r\n");

      f.write("Available employee work weeks: "+ W + "\r\n");

      f.write("Number of projects chosen: "+ count + "\r\n");

      f.write("Total profit: "+ maxProfit + "\r\n");

     

  for (int j = 0; j < count; j++)

  f.write("\nProject"+ projectIncluded[j] +" " +wk[projectIncluded[j]]+ " "+ pr[projectIncluded[j]] + "\r\n");

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  public static void main(String[] args) throws Exception

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  int count = 0;

  while (fl.hasNextLine()){

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  }

 

  knapsack(workWeeks, profit, avbWeeks, outputFile);

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Console Output:

Enter the number of available employee work weeks: 10

Enter the name of input file: input.txt

Enter the name of output file: output.txt

Number of projects = 4

Output.txt:

Number of projects available: 4

Available employee work weeks: 10

Number of projects chosen: 2

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Answer:

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Explanation:

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Z = number of atom in unit cell

M = atomic mass

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a = edge length of unit cell

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Z = 2 (BCC)

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Edge length of the unit cell = a

r = 0.866 a (BCC unit cell)

a=\frac{0.143 nm}{0.866}=0.165 nm=0.165 \times 10^{-7} cm

1 nm = 10^{-7} cm

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\rho=\frac{2\times 92.91}{6.022\times 10^{23} mol^{-1}\times (0.165 \times 10^{-7} cm)^{3}}

\rho =1.87 g/cm^3

The theoretical density for Niobium is 1.87 g/cm^3.

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