Question

2. A F-22 Raptor has just climbed through an altitude of 9,874 m at 1,567 kph when a disk

Answer 1

The pressure difference across the sensor housing will be "95 kPa".

According to the question, the values are:

Altitude,

• 9874

Speed,

• 1567 kph

Pressure,

• 122 kPa

The temperature will be:

→ $T = 15.04-[0.00649(9874)]$

→     $= 15.04-64.082$

→     $= -49.042^{\circ} C$

now,

→ $P_o = 101.29[\frac{(-49.042+273.1)}{288.08} ]^{(5.256)}$

→      $= 27.074$

hence,

→ The pressure differential will be:

= $122-27$

= $95 \ kPa$

Thus the above solution is correct.

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