2. A F-22 Raptor has just climbed through an altitude of 9,874 m at 1,567 kph when a disk
1 answer:
The pressure difference across the sensor housing will be "95 kPa".
According to the question, the values are:
Altitude,
- 9874
Speed,
- 1567 kph
Pressure,
- 122 kPa
The temperature will be:
→
→
→
now,
→
→
hence,
→ The pressure differential will be:
=
=
Thus the above solution is correct.
Learn more about pressure difference here:
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Answer:
the percent increase in the velocity of air is 25.65%
Explanation:
Hello!
The first thing we must consider to solve this problem is the continuity equation that states that the amount of mass flow that enters a system is the same as what should come out.
m1=m2
Now remember that mass flow is given by the product of density, cross-sectional area and velocity
(α1)(V1)(A1)=(α2)(V2)(A2)
where
α=density
V=velocity
A=area
Now we can assume that the input and output areas are equal
(α1)(V1)=(α2)(V2)
Now we can use the equation that defines the percentage of increase, in this case for speed
Now we use the equation obtained in the previous step, and replace values
the percent increase in the velocity of air is 25.65%
Answer:
a) (Ω-m)^{-1}
b) Resistance = 121.4 Ω
Explanation:
given data:
diameter is 7.0 mm
length 57 mm
current I = 0.25 A
voltage v = 24 v
distance between the probes is 45 mm
electrical conductivity is given as
(Ω-m)^{-1}[/tex]
b)
Resistance = 121.4 Ω