3 years ago

Help!!!!! Help please !!!!!!

Mathematics

2 answers:

Ivahew [28]3 years ago

8 0

Step-by-step explanation:

um I will help mmmmmmmmmm

Helen [10]3 years ago

8 0

I honestly don’t know ..

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I WILL GIVE 20 POINTS TO THOSE WHO ANSWER THIS QUESTION RIGHT NOOOO SCAMS AND EXPLAIN WHY THAT IS THE ANSWER

Firdavs [7]

2x+20=58 then your would subtract 20 from 58 which would turn into 38 and your would divide 38/2 it would be 19 so the answer is x=19 if I’m not mistaken this is correct hope this helps

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2 years ago

Solve for x of the triangle x^2=3x7

Tju [1.3M]

4.58

Sq rt of 21 3x7= 21

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3 years ago

If the length of a rectangle is

EastWind [94]

I think that the length's area is 6075

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2 years ago

Assume that the terminal side of thetaθ passes through the point (negative 12 comma 5 )(−12,5) and find the values of trigonomet

zmey [24]

Answer:

$\sin \theta = \dfrac{5}{13}$ and $\sec \theta = -\dfrac{13}{12}$

Step-by-step explanation:

Assume that the terminal side of thetaθ passes through the point (−12,5).

In ordered pair (-12,5), x-intercept is negative and y-intercept is positive. It means the point lies in 2nd quadrant.

Using Pythagoras theorem:

$hypotenuse^2=perpendicular^2+base^2$

$hypotenuse^2=(5)^2+(12)^2$

$hypotenuse^2=25+144$

$hypotenuse^2=169$

Taking square root on both sides.

$hypotenuse=13$

In a right angled triangle

$\sin \theta = \dfrac{opposite}{hypotenuse}$

$\sin \theta = \dfrac{5}{13}$

$\sec \theta = \dfrac{hypotenuse}{adjacent}$

$\sec \theta = \dfrac{13}{12}$

In second quadrant only sine and cosecant are positive.

$\sin \theta = \dfrac{5}{13}$ and $\sec \theta = -\dfrac{13}{12}$

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3 years ago

Find the value of x. The angle measures of a right triangle are 30° 2x° 3x°

Radda [10]

Answer:

Step-by-step explanation:

Exterior angle equals sum of opposite interior angles

3x = 2x + 30

3x - 2x = 30

x = 30

3 0

2 years ago

Read 2 more answers