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quester [9]
3 years ago
11

How many grams are in 0.040 moles zirconium (Zr)?

Chemistry
2 answers:
sveticcg [70]3 years ago
8 0

Answer:

3.64896 grams Zr

Explanation:

Given: amount of moles of Zr: 0.040

Find: the amount of grams of Zr

1. Find molar mass of Zr

- after looking at the periodic table, you can tell it's 91.224 g/mol

2. Solve

(\frac{0.040 mol Zr}{1})( \frac{91.224 g Zr}{1 mol Zr})

- the mol units get cancelled out, and you're left with 0.040 x 91.224 g

3. Multiply that out: 3.64896 grams of zirconium

Anton [14]3 years ago
7 0

Answer:

91.224 gram

Explanation:

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Consider the titration of 1L of 0.36 M NH3 (Kb=1.8x10−5) with 0.74 M HCl. What is the pH at the equivalence point of the titrati
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Answer:

C

Explanation:

The question asks to calculate the pH at equivalence point of the titration between ammonia and hydrochloric acid

Firstly, we write the equation of reaction between ammonia and hydrochloric acid.

NH3(aq)+HCl(aq)→NH4Cl(aq)

Ionically:

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Firstly, we calculate the number of moles of  the ammonia  as follows:

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An ICE TABLE IS USED TO FIND THE CONCENTRATION OF THE HYDROXONIUM ION(H3O+). ICE STANDS FOR INITIAL, CHANGE AND EQUILIBRIUM.

                 NH4+      H2O     ⇄  NH3        H3O+

I                0.242                           0             0

C                 -X                              +x              +X

E             0.242-X                          X              X

Since the question provides us with the base dissociation constant value K b, we can calculate the acid dissociation constant value Ka

To find this, we use the mathematical equation below

K a ⋅ K b    = K w

 

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This means that you have

K a = K w.K b   = 10 ^− 14 /1.8 * 10^-5 =  5.56 * 10^-10

Ka = [NH3][H3O+]/[NH4+]

= x * x/(0.242-x)

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x^2 = 0.242 * 5.56 * 10^-10 = 1.35 * 10^-10

x = 0.00001161895

[H3O+] = 0.00001161895

pH = -log[H3O+]

pH = -log[0.00001161895 ] = 4.94

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