How many grams are in 0.040 moles zirconium (Zr)?
2 answers:
Answer:
3.64896 grams Zr
Explanation:
Given: amount of moles of Zr: 0.040
Find: the amount of grams of Zr
1. Find molar mass of Zr
- after looking at the periodic table, you can tell it's 91.224 g/mol
2. Solve
()(
)
- the mol units get cancelled out, and you're left with 0.040 x 91.224 g
3. Multiply that out: 3.64896 grams of zirconium
You might be interested in
Answer: Option (d) is the correct answer.
Explanation:
It is given that molecular formula is . Now, we will calculate the degree of unsaturation as follows.
Degree of unsaturation =
=
= 9 - 8 + 1
= 2
As the degree of unsaturation comes out to be 2. It means that this compound will contain one ring and one double bond.
Yes, this compound could be an alkyne as for alkyne D.B.E = 2.
But this compound cannot be a cycloalkane because for a cycloalkane D.B.E = 1 which is due to the ring only.
Thus, we can conclude that it is a cycloalkane is not a structural possibility for this hydrocarbon.