(8.08x10^24 H atoms)(3 C atoms/8 H atoms)
=3.03x10^24 C atoms
3.03x10^24+8.08x10^24=1.111x10^25 atoms total
(1.111x10^25)/(6.02x10^23)=18.4551495 mol C3H8
18.4551495(44.01)=812.2111296g C3H8
Answer:
1.1: Taking Measurements. Chemists measure the properties of matter and express these measurements as quantities. A quantity is an amount of something and consists of a number and a unit. The number tells us how many (or how much), and the unit tells us what the scale of measurement is.
Answer:
The correct answer is liters , grams, degrees Celsius
Explanation:
The metric system is called also international system of units with this short symbols (SI) , It consists of many base units which can measure any physical amount or quantity .example for this bas units the Liters to measure volume, the kilogram and gram to measure the mass , Celsius degrees to measure the temperature using thermometers , also Ampire for measuring the current of the electricity and the second in measuring the time
but quarts , degrees fahrenheit and pints are parts of the imperial system
The balanced equation for the reaction is as follows
6H₂O + 6CO₂ ---> C₆H₁₂O₆ + 6O₂
number of moles of CO₂ used - 44 g / 44 g/mol = 1 mol
number of moles of H₂O used - 18 g / 18 g/mol = 1 mol
stoichiometry of CO₂ to H₂O is 6:6 = 1:1
1 mol of CO₂ present and 1 mol of H₂O present therefore they are both fully used up in the reaction of molar ratio 1:1
number of moles of O₂ formed - 32 g/ 32 g/mol = 1 mol
stoichiometry of CO₂:H₂O:C₆H₁₂O₆:O₂ is 6:6:1:6
1 mol of CO₂ has reacted with 1 mol of H₂O to form 1 mol of O₂ and x mol of C₆H₁₂O₆
the number of C₆H₁₂O₆ moles is 1/6th of CO₂ moles used up
since CO₂ moles - 1 mol
therefore C₆H₁₂O₆ moles formed - 1/6 mol = 0.167 mol
mass of glucose formed - 0.167 g x 180 g/mol = 30 g
therefore 30 g of glucose is formed
Answer: I believe the answer you are looking for is 0.02180
