Carbon disulfide ( S=C=S) is made up of one carbon atom and two sulfur atom.
Carbon has 4 valence electrons while sulfur has 6 electrons.
During bonding all the four carbon valence electrons are used in bonding while each sulfur atom contributes two electrons two the bond formation.
Therefore; 4 + 2(2) = 8 electrons are used for bonding, while 8 electrons ( four from each sulfur atom) are not used for bond formation.
Answer:
16.8%
Explanation:
31% NaOH molar mass 40 gm
69% H2O molar mass 18 gm
1000 gm would be
310 gm NaOH or 310/40 = 7.75 moles
690 gm of H2O or 690/18 = 38.333 moles
7.75 / (7.75 + 38.333) = .168 mole fraction
Answer:
I'm hoping this helps!! it's on quizzes if you're wondering
Answer : The fugacity in the solution is, 16 bar.
Explanation : Given,
Fugacity of a pure component = 40 bar
Mole fraction of component = 0.4
Lewis-Randall rule : It states that in an ideal solution, the fugacity of a component is directly proportional to the mole fraction of the component in the solution.
Now we have to calculate the fugacity in the solution.
Formula used :

where,
= fugacity in the solution
= fugacity of a pure component
= mole fraction of component
Now put all the give values in the above formula, we get:


Therefore, the fugacity in the solution is, 16 bar.
0.250 L*3M=0.250 L*3mol/L= 0.750 mol