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2 years ago

What is the most basic level of biological organization?

Chemistry

2 answers:

Alja [10]2 years ago

7 0

Answer:

Explanation:

Brums [2.3K]2 years ago

5 0

Answer:

molecule

Explanation:

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Lime is an alkaline substance which is sometimes put onto acidic soils.

VARVARA [1.3K]

Explanation:Your soil is acidic and you would like to change the pH so that it is less acidic. The universal advice is to add lime to the soil ie liming your soil. Lime is alkaline and it will neutralize the acidity of the soil and make it more neutral. Adding lime certainly works

5 0

2 years ago

Consider the following reaction of the commercial production of SO3 using sulfur dioxide and oxygen: SO2(g) + O2(g) → SO3(g)

kipiarov [429]

Answer:

$m_{SO_3}=18.93gSO_3$

$V_{SO_3}=5.3LSO_3$

Explanation:

Hello,

STP conditions are P=1 atm and T=273.15 K, thus, the reacting moles are:

$n_{SO_2}=\frac{5.3L*1atm}{0.082\frac{atm*L}{mol*K}*273.15K}=0.2366molSO_2\\n_{O_2}=\frac{4.7L*1atm}{0.082\frac{atm*L}{mol*K}*273.15K}=0.2098molO_2$

Now, the balanced chemical reaction turns out into:

$2SO_2(g) + O_2(g) --> 2SO_3(g)$

Thus, the exact moles of oxygen that completely react with 0.2366 moles of sulfur dioxide are (limiting reagent identification):

$0.2366molSO_2*\frac{1molO_2}{2molSO_2}=0.1182molO_2$

Since 0.2098 moles of oxygen are available, we stipulate the oxygen is in excess and the sulfur dioxide is the limiting reagent. In such a way, the yielded grams of sulfur trioxide turn out into:

$m_{SO_3}=0.2366molSO_2*\frac{2molSO_3}{2molSO_2}*\frac{80gSO_3}{1molSO_3} \\m_{SO_3}=18.93gSO_3$

By using the ideal gas equation, one computes the volume as:

$V_{SO_3}=\frac{mRT}{MP}=\frac{18.93g*0.082\frac{atm*L}{mol*K} *273.15K}{80g/mol*1atm}\\V_{SO_3}=5.3LSO_3$

It has sense for volume since the mole ratio is 2/2 between sulfur dioxide and sulfur trioxide.

Best regards.

6 0

3 years ago

If 38.55 mL of HCl is required to titrate 2.150 g of Na2CO3 according to the following equation, what is the molarity of the HCl

monitta

The molarity of the HCl solution : 1.052 M

<h3>Further explanation</h3>

Given

Volume of HCl = 38.55 ml

mass of Na₂CO₃ (MW=106 g/mol)=2.15 g

Reaction

Na₂CO₃(aq) + 2HCl (aq)→ 2NaCl (aq) + CO₂ (g) + H₂0 (l)

Required

The molarity of the HCl solution

Solution

mol Na₂CO₃ :

$\tt mol=\dfrac{mass}{MW}=\dfrac{2.15}{106}=0.02028$

From the equation, mol ratio Na₂CO₃ : HCl = 1 : 2, so mol HCl :

$\tt mol~HCl=2\times 0.02028=0.04056$

The molarity :

$\tt M=\dfrac{n}{V}=\dfrac{0.04056}{0.03855~L}=1.052~M$

7 0

2 years ago

Describe the structure of atoms, including locations and charges of protons, neutrons, and electrons

pantera1 [17]

In an atom, the protons, which have a positive charge, and the neutrons, which have a neutral charge, are located in the nucleus. The electrons, which have a negative charge, orbit the nucleus of the atom.

3 0

2 years ago

How red blood cells different to animal cells

barxatty [35]

Answer:

By contrast, the red blood cells of mammals lack nuclei and other internal structures found in most animal cells. This simplification allows mammal red blood cells to carry more gas-transporting proteins and to squeeze through smaller blood vessels.

Explanation:

4 0

2 years ago