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KengaRu [80]
3 years ago
15

How many moles of KCLO4 can be produced with 3.45 moles of NaCl. Assume all other reactants are in excess

Chemistry
1 answer:
ycow [4]3 years ago
4 0
NOTE question is incorrect: The question should be:
<span>How many moles of KCLO4 can be produced with 3.45 moles of KCl. Assume all other reactants are in excess.
.......................................................................................................................

The reaction involving formation of KClO4 is 

NaClO4      +       KCl     </span>→    KClO4       +       NaCl

From above reaction, it can be seen that 1 mole of NaClO4 reacts with 1 mole of KCl to generate 1 mole of KClO4

Thus, if all other reactant are in excess, 3.45 moles of KCl  will react with 3.45 moles of NaClO4 to form 3.45 moles of KClO4.
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when we convert 32.5 lb/in² to atmosphere, the result obtained is 2.21 atm

<h3>Conversion scale</h3>

14.6959 lb/in² = 1 atm

<h3>Data obtained from the question</h3>
  • Pressure (in lb/in²) = 32.5 lb/in²
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<h3>How to convert 32.5 lb/in² to atm</h3>

14.6959 lb/in² = 1 atm

Therefore

32.5 lb/in² = 32.5 / 14.6959

32.5 lb/in² = 2.21 atm

Thus, 32.5 lb/in² is equivalent to 2.21 atm

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<h3>Further explanation  </h3>

Titration is a procedure for determining the concentration of a solution (analyte) by reacting with another solution whose known concentration (usually a standard solution) is called the titrant. Determination of the endpoint/equivalence point of the reaction can use indicators according to the appropriate pH range  

Titrations can be acid-base titration, depositional titration, and redox titration. An acid-base titration is the principle of neutralization of acids and bases  

Reaction

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\tt mol=M\times V\\\\mol=0.0998\times 25\\\\mol=2.495~mlmoles

<em>From the equation, mol ratio HNO₃ : NaOH = 1 : 1, so mol HNO₃ = mol NaOH=</em><em>2.495 mlmoles</em>

<em></em>

The volume of HNO₃ = 21.8 cm³, so the concentration :

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2 years ago
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