The expected final temperature of the block, given that 586 J of heat were added to it is 55.5 °C
<h3>How to determine the final temeprature</h3>
We'll begin by obtaining the change in the temperature of the block. This can be obtained as follow:
- Specific heat capacity of block (C) = 0.240 J/gºC
- Heat added (Q) = 586 J
- Mass of block (M) = 80.0 g
- Change in temperature (ΔT) =?
Q = MCΔT
Divide both sides by MC
ΔT = Q / MC
ΔT = 586 / (80.0 × 0.240)
ΔT = 586 / 19.2
ΔT = 30.5 °C
Finally, we shall determine the final temperature of the block. This can be obtained as follow:
- Initial temperature (T₁) = 25 °C
- Change in temperature (ΔT) = 30.5 °C
- Final temperature (T₂) = ?
ΔT = T₂ – T₁
30.5 = T₂ – 25
Collect like terms
T₂ = 30.5 + 25
T₂ = 55.5 °C
Thus, from the calculation made above, we can conclude that the final temperature is 55.5 °C
Learn more about heat transfer:
brainly.com/question/14383794
#SPJ1
It will not tip over a hot plate
Answer:
C. some substances can move freely across the cell membrane, while others must be transported.
Explanation:
Answer:
Temperature and pressure are the two factors which are responsible for change in state of matter.
Solid – In a solid, the attractive forces keep the particles together tightly enough so that the particles do not move past each other. ... In the solid the particles vibrate in place. Liquid – In a liquid, particles will flow or glide over one another, but stay toward the bottom of the container.
<em>Hope this helps, mark as Brainliest please...</em>
Answer:
The sestira structure makes the poem feel like a playful puzzle, but aciels nothing to the meaning of the poem
The repetition of the last word in each line creates a reflective rhythm and tone in the poem while also making significant words
easily recognizable
Explanation:
That was a really good one, I think you may want to go with that answer.