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yulyashka [42]
3 years ago
6

Choosing a member of the math club and a member of the science club?​

Mathematics
2 answers:
Alexus [3.1K]3 years ago
8 0
Huh I am quite confused
nydimaria [60]3 years ago
7 0

What do you mean Answer:

Step-by-step explanation:

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A ball is thrown from an initial height of 1 meter with an initial upward velocity of 15m/s. The ball's height h (in meters) aft
lakkis [162]

\bf \stackrel{\textit{ball's height}~\hfill }{\stackrel{\downarrow }{h}=1+15t-5t^2}\implies \stackrel{\textit{ball's height}~\hfill }{\stackrel{\downarrow }{6}=1+15t-5t^2}\implies 0=-5+15t-5t^2 \\\\\\ ~~~~~~~~~~~~\textit{using the quadratic formula} \\\\ \stackrel{\stackrel{a}{\downarrow }}{5}t^2\stackrel{\stackrel{b}{\downarrow }}{-15}t\stackrel{\stackrel{c}{\downarrow }}{+5}=0 \qquad \qquad t= \cfrac{ - b \pm \sqrt { b^2 -4 a c}}{2 a}

\bf t=\cfrac{-(-15)\pm\sqrt{(-15)^2-4(5)(5)}}{2(5)}\implies t=\cfrac{15\pm\sqrt{225-100}}{10} \\\\\\ t=\cfrac{15\pm\sqrt{125}}{10}\implies t=\cfrac{15\pm\sqrt{5^2 \cdot 5}}{10}\implies t=\cfrac{\stackrel{3}{~~\begin{matrix} 15 \\[-0.7em]\cline{1-1}\\[-5pt]\end{matrix}~~}\pm ~~\begin{matrix} 5 \\[-0.7em]\cline{1-1}\\[-5pt]\end{matrix}~~\sqrt{5}}{\underset{2}{~~\begin{matrix} 10 \\[-0.7em]\cline{1-1}\\[-5pt]\end{matrix}~~}}

\bf t=\cfrac{3\pm \sqrt{5}}{2}\implies t= \begin{cases} \frac{3+ \sqrt{5}}{2} \approx 2.618\\\\ \frac{3- \sqrt{5}}{2}\approx 0.382 \end{cases}

8 0
2 years ago
Find the volume of a right circular cone that has a height of 6.7 in and a base with a diameter of 8.8 in. Round your answer to
N76 [4]

Answer: 135.8

Step-by-step explanation:

the formula for this is πr²H/3

π4.4^2x6.7/3

407.5/3

135.8

4 0
2 years ago
Please help me pleaseee
jekas [21]

Answer: A - sin 63

Step-by-step explanation:

3 0
2 years ago
PLEASE HURRY IT DO THE NEXT DAY PLZ HELP ME
liberstina [14]
The Bulldogs are least likely to win.
7 0
3 years ago
Read 2 more answers
PLZZZZZZZZZZZZZZZZZ HELP!
Svet_ta [14]

answer: -5x+12=20

                   -12    -12

            -5x/-5= 8/-5

             x= -1.6

       Check: rewrite the orignal problem

          plug your variable

       

             

5 0
3 years ago
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