Chang and Charla solve this problem in two different ways.

What is the value of x in the equation 8x – 2y = 48, when y = 4? 6 ОО 7 O 14 48

Otrada [13]

The value of x is 7........

6 0

3 years ago

Carson has a package to mail. The package is 87 cm long. The shipping company only mails packages that are up to 35 in. long. Ca

m_a_m_a [10]

Based on the conversion done, the figure gotten is larger. Therefore, Carson cannot mail the package

From the information given, the package is 87 cm long.

Also, the shipping company only mails packages that are up to 35 in. long. Then, we convert inches to cm. This will be:

= 35 × 2.54 = 88.9 cm.

Therefore, he can't mail the package.

Learn more about conversion on:

brainly.com/question/25828084

7 0

3 years ago

(1/1+sintheta)=sec^2theta-secthetatantheta pls help me verify this

Xelga [282]

Answer:

See Below.

Step-by-step explanation:

We want to verify the equation:

$\displaystyle \frac{1}{1+\sin\theta} = \sec^2\theta - \sec\theta \tan\theta$

To start, we can multiply the fraction by (1 - sin(θ)). This yields:

$\displaystyle \frac{1}{1+\sin\theta}\left(\frac{1-\sin\theta}{1-\sin\theta}\right) = \sec^2\theta - \sec\theta \tan\theta$

Simplify. The denominator uses the difference of two squares pattern:

$\displaystyle \frac{1-\sin\theta}{\underbrace{1-\sin^2\theta}_{(a+b)(a-b)=a^2-b^2}} = \sec^2\theta - \sec\theta \tan\theta$

Recall that sin²(θ) + cos²(θ) = 1. Hence, cos²(θ) = 1 - sin²(θ). Substitute:

$\displaystyle \displaystyle \frac{1-\sin\theta}{\cos^2\theta} = \sec^2\theta - \sec\theta \tan\theta$

Split into two separate fractions:

$\displaystyle \frac{1}{\cos^2\theta} -\frac{\sin\theta}{\cos^2\theta} = \sec^2\theta - \sec\theta\tan\theta$

Rewrite the two fractions:

$\displaystyle \left(\frac{1}{\cos\theta}\right)^2-\frac{\sin\theta}{\cos\theta}\cdot \frac{1}{\cos\theta}=\sec^2\theta - \sec\theta \tan\theta$

By definition, 1 / cos(θ) = sec(θ) and sin(θ)/cos(θ) = tan(θ). Hence:

$\displaystyle \sec^2\theta - \sec\theta\tan\theta \stackrel{\checkmark}{=} \sec^2\theta - \sec\theta\tan\theta$

Hence verified.

8 0

3 years ago

Make a conjecture about the diagram below. Do you think you can conclude that △JKL ≅ △XYZ? Explain your reasoning.

konstantin123 [22]

Answer:

Yes, you can conclude that ΔJKL ≅ XYZ.

Step-by-step explanation:

I forget how to describe it in geometric terms but, if you read the similarity statement again, and follow each angle, you'll notice that the shapes match, and they correspond to each other, it would be different if it said something like ΔLKJ ≅ XYZ because it does not match.

If you're looking for a specific reason, we'd say that they're congruent because of SAS (Side-Angle-Side)

If this still confuses you, hit me up.

6 0

3 years ago

Read 2 more answers

Part 1: How's the weather? A. Investigate the weather forecast in your city. Record the high and low temperatures that are forec

victus00 [196]

Using the mean concept, it is found that:

1. The mean change in the forecasted high temperatures is of -0.33ºC.

2. The mean change in the forecasted low temperatures is of 0.5ºC.

-----------------------------

The mean of data-set is given by the sum of all observations divided by the number of observations.

Item 1:

The changes in the high temperature are: 2, 1, -1, -1, -1, -2

Thus:

$M = \frac{2 + 1 - 1 - 1 - 1 - 2}{6} = -0.33$

The mean change in the forecasted high temperatures is of -0.33ºC.

Item 2:

The changes in the low temperature are: 2, -2, 2, 1, 0, 0.

$M = \frac{2 - 2 + 2 + 1 + 0 + 0}{6} = 0.5$

The mean change in the forecasted low temperatures is of 0.5ºC.

A similar problem is given at brainly.com/question/24754716

3 0

2 years ago