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erik [133]
3 years ago
15

I'm struggling with this question

Mathematics
1 answer:
tekilochka [14]3 years ago
4 0

It is very blurry, I'm so sorry

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lawyer [7]
After 1 year=x1.1
After 2 years=x1.1*1.1
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After 5 years=x1.1*1.1*1.1*1.1*1.1=x1.61051
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What is a cubic polynomial function with zeros 3,3 and -3? show your work.​
Brums [2.3K]

Answer:

Cubic polynomial function with zeros 3,3 and -3 is \mathbf{x^3-3x^2-9x+27=0}

Step-by-step explanation:

We need to find a cubic polynomial function with zeros 3,3 and -3.

If zeros of polynomial are: 3,3,and -3

we can write:

x=3, x=3, x=-3

Or

We can write:

x-3=0, x-3=0, x+3=0

Now, we can write them as:

(x-3)(x-3)(x+3)=0

Multiplying the terms, we can find the polynomial:

(x-3)(x-3)(x+3)=0\\(x(x-3)-3(x-3))(x+3)=0\\(x^2-3x-3x+9)(x+3)=0\\(x^2-6x+9)(x+3)=0\\x(x^2-6x+9)+3(x^2-6x+9)=0\\x^3-6x^2+9x+3x^2-18x+27=0\\x^3-6x^2+3x^2+9x-18x+27=0\\x^3-3x^2-9x+27=0

So, cubic polynomial function with zeros 3,3 and -3 is \mathbf{x^3-3x^2-9x+27=0}

4 0
3 years ago
Absolute value -30 minus absolute value -4 plus absolute value 5=
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Answer:

31

Step-by-step explanation:

|-30| - |-4| + |5| = 30 - 4 + 5 = 31

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-5, 2.4, -2.25, -8, -12

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4 years ago
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