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Nuetrik [128]
3 years ago
8

Hydrofluoric acid and water react to form fluoride anion and hydronium cation, like this:

Chemistry
1 answer:
Sliva [168]3 years ago
4 0

Answer: The value of the equilibrium constant is 0.000023.

Explanation:

Equilibrium concentration of HF = \frac{1.62g}{20.01g/mol\times 5.6L}=0.014M

Equilibrium concentration of H_2O = \frac{516g}{18g/mol\times 5.6L}=5.12M

Equilibrium concentration of F^- = \frac{0.163g}{18.9g/mol\times 5.6L}=0.0015M

Equilibrium concentration of H_3O^+ = \frac{0.110g}{18g/mol\times 5.6L}=0.0011M

 The given balanced equilibrium reaction is,

                 HF(aq)+H_2O(l)\rightleftharpoons F^-(aq)+H_3O^+(aq)

The expression for equilibrium constant for this reaction will be,

K_c=\frac{[F^-]\times [H_3O^+]}{[HF]\times [H_2O]}

K_c=\frac{(0.0015\times 0.0011}{(0.014\times 5.12)}

K_c=0.000023

Thus the value of the equilibrium constant is 0.000023.

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