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geniusboy [140]
3 years ago
7

What is the chemical formula of the salt produced by the neutralization of potassium hydroxide with sulfuric acid?KSO3KSO4K(SO4)

2K2SO4K2(SO4)3
Chemistry
1 answer:
kakasveta [241]3 years ago
6 0

Answer: The salt produced will be K_{2}SO_{4}

Explanation:

During a neutralization reaction, an acid reacts with a base for producing the correspondent salt, and water.

The strong acids release all the protons avalaible when are dissolved, such as sulfuric acid. As you can see, sulfuric acid have 2 protons ready for being released (H_{2}SO_{4}); and those places have to be occcupied for other ions equivalents to the H+: K+ from KOH in this case.

Therefore the answer will be K_{2}SO_{4}.

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there are tiny plants growing on rock fence after the several year . you observe something happened on the rock which of the fol
Bingel [31]

it is moss

Explanation:

5 0
3 years ago
Carbon monoxide (CO) reacts with hydrogen (H2) to form methane (CH4) and water (H2O).
Artemon [7]

Answer:

5.9x10^-2 M

Explanation:

Step 1:

Data obtained from the question. This includes the following:

Concentration of CO, [CO] = 0.30 M

Concentration of H2, [H2] = 0.10 M

Concentration of H2O, [H2O] = 0.020 M

Equilibrium constant, K = 3.90

Concentration of CH4, [CH4] =..?

Step 2:

The balanced equation for the reaction. This is given below:

CO(g) + 3H2(g) <=> CH4(g) + H2O(g)

Step 3:

Determination of the concentration of CH4.

The expression for equilibrium constant of the above equation is given below:

K = [CH4] [H2O] / [CO] [H2]^3

3.9 = [CH4] x 0.02/ 0.3 x (0.1)^3

Cross multiply to express in linear form

[CH4] x 0.02= 3.9 x 0.3 x (0.1)^3

Divide both side by 0.02

[CH4] = 3.9 x 0.3 x (0.1)^3 /0.02

[CH4] = 5.9x10^-2 M

Therefore, the equilibrium concentration of CH4 is 5.9x10^-2 M

5 0
3 years ago
What is one differrence between a mixture and a compound
Ann [662]

Answer:

A mixture can contain components in any proportions while a compound contains components in fixed proportions. All components in a mixture do not chemically react, while the components in a compound do react and their original properties are lost.

3 0
3 years ago
Copper(II) sulfide is formed when copper and sulfur are heated together. In this reaction,
storchak [24]

Answer:

The mass of copper(II) sulfide formed is:

= 81.24 g

Explanation:

The Balanced chemical equation for this reaction is :

Cu(s) + S\rightarrow CuS

given mass= 54 g

Molar mass of Cu = 63.55 g/mol

Moles = \frac{given\ mass}{Molar\ mass}

moles=\frac{54}{63.55}

Moles of Cu = 0.8497 mol

Given mass = 42 g

Molar mass of S = 32.06 g/mol

Moles = \frac{given\ mass}{Molar\ mass}

moles=\frac{42}{32.06}

Moles of S = 1.31 mol

Limiting Reagent :<em> The reagent which is present in less amount and consumed in a reactio</em>n

<u><em>First find the limiting reagent :</em></u>

Cu + S\rightarrow CuS

1 mol of Cu require = 1 mol of S

0.8497 mol of Cu should require  = 1 x 0.8497 mol

= 0.8497 mol of S

S present in the reaction Medium = 1.31 mol

S Required  = 0.8497 mol

S is present in excess and <u>Cu is limiting reagent</u>

<u>All Cu is consumed in the reaction</u>

Amount Cu will decide the amount of CuS formed

Cu + S\rightarrow CuS

1 mole of Cu  gives = 1 mole of Copper sulfide

0.8497 mol of Cu =  1 x 0.8497 mole of Copper sulfide

= 0.8497

Molar mass of CuS = 95.611 g/mol

Moles = \frac{given\ mass}{Molar\ mass}

0.8497 = \frac{given\ mass}{95.611}

Mass of CuS = 0.8497 x 95.611

= 81.24 g

3 0
3 years ago
How many moles of h2o are produced when 3.25 moles of o2 react in 2c2h6 + 7o2 ---&gt; 4co2 + 6h2o
Alenkinab [10]

Answer:

2.78 moles of water are produced.

Explanation:

Given data:

Number of moles of H₂O produced = ?

Number of moles of oxygen react = 3.25 mol

Solution:

Chemical equation:

2C₂H₆ + 7O₂       →     4CO₂ + 6H₂O

Now we will compare the moles of water with oxygen.

                O₂          :          H₂O

                 7            :           6

               3.25        :           6/7×3.25 = 2.78 mol

5 0
3 years ago
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