Answer:
a.) tanL= 0.533
b.) sinN= 0.882
c.) cosN= 0.471
Step-by-step explanation:
Triangle ABC is similar to Triangle LMN, which means that their corresponding angles are congruents.
Using SOH-CAH-TOA we have,
tanL~tanA= 8/15 = 0.533
sinN~sinC= 15/17 = 0.882
cosN~cosC= 8/17 = 0.471
Answer:
11
Step-by-step explanation:
#4 .
x + 8 - 8 = 7 - 8
It's "Subtraction property of equality"
It's correct
Answer:
thus the probability that a part was received from supplier Z , given that is defective is 5/6 (83.33%)
Step-by-step explanation:
denoting A= a piece is defective , Bi = a piece is defective from the i-th supplier and Ci= choosing a piece from the the i-th supplier
then
P(A)= ∑ P(Bi)*P(C) with i from 1 to 3
P(A)= ∑ 5/100 * 24/100 + 10/100 * 36/100 + 6/100 * 40/100 = 9/125
from the theorem of Bayes
P(Cz/A)= P(Cz∩A)/P(A)
where
P(Cz/A) = probability of choosing a piece from Z , given that a defective part was obtained
P(Cz∩A)= probability of choosing a piece from Z that is defective = P(Bz) = 6/100
therefore
P(Cz/A)= P(Cz∩A)/P(A) = P(Bz)/P(A)= 6/100/(9/125) = 5/6 (83.33%)
thus the probability that a part was received from supplier Z , given that is defective is 5/6 (83.33%)
Answer:

Step-by-step explanation:
Distribute (2h − 3k)(h + 5k).
2h^2 + 10hk - 3hk - 15k^2
2h^2 + 7hk 15k^2